Yes
The value of (5C2) is calculated using the combination formula (nCr = \frac{n!}{r!(n-r)!}). Here, (n = 5) and (r = 2), so (5C2 = \frac{5!}{2!(5-2)!} = \frac{5!}{2! \cdot 3!} = \frac{5 \times 4}{2 \times 1} = 10). Thus, (5C2 = 10).
(5c - 2)(c +1)
There are 5C2 = 5*4/(2*1) = 10 combinations.
The probability of drawing two jacks and three tens of any suite from a standard deck of cards is: 5C2 ∙ (4/52)∙(3/51)∙(4/50)∙(3/49)∙(2/48) = 0.00000923446... ≈ 0.0009234% where 5C2 = 5!/[(5-2)!∙(2!)] = 10
Yes
he can choose the answer in this way, 5c1*5c3+5c2*5c2+5c3*5c1 evaluate, the answer will be 200.
(5c - 2)(c +1)
No. A monomial cannot have the variable c to different powers.
There are 5C2 = 5*4/(2*1) = 10 combinations.
The probability of drawing two jacks and three tens of any suite from a standard deck of cards is: 5C2 ∙ (4/52)∙(3/51)∙(4/50)∙(3/49)∙(2/48) = 0.00000923446... ≈ 0.0009234% where 5C2 = 5!/[(5-2)!∙(2!)] = 10
7/30 cannot be simplified.7/30 cannot be simplified.7/30 cannot be simplified.7/30 cannot be simplified.
It can not be simplified further.
It is simplified.
No it can not be simplified
10.9 cannot be simplified.
67.5 cannot be simplified.