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The expression (5c2) represents the number of combinations of 5 items taken 2 at a time. It can be calculated using the formula ( \frac{n!}{r!(n-r)!} ), where (n) is the total number of items and (r) is the number of items to choose. For (5c2), this equals ( \frac{5!}{2!(5-2)!} = \frac{5!}{2! \cdot 3!} = \frac{5 \times 4}{2 \times 1} = 10). Therefore, (5c2) simplifies to 10.
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Is c3-5c2-36c a trinomial?
Yes
What is the value of 5C2?
The value of (5C2) is calculated using the combination formula (nCr = \frac{n!}{r!(n-r)!}). Here, (n = 5) and (r = 2), so (5C2 = \frac{5!}{2!(5-2)!} = \frac{5!}{2! \cdot 3!} = \frac{5 \times 4}{2 \times 1} = 10). Thus, (5C2 = 10).
Factor of 5C2 plus 3C-2?
(5c - 2)(c +1)
What is the number of combinations for 2 out of 5 events?
There are 5C2 = 5*4/(2*1) = 10 combinations.
What is the probability of drawing two jacks and 3 tens of any suite from a standard deck of cards?
The probability of drawing two jacks and three tens of any suite from a standard deck of cards is: 5C2 ∙ (4/52)∙(3/51)∙(4/50)∙(3/49)∙(2/48) = 0.00000923446... ≈ 0.0009234% where 5C2 = 5!/[(5-2)!∙(2!)] = 10
Is c3-5c2-36c a trinomial?
Yes
What is the value of 5C2?
The value of (5C2) is calculated using the combination formula (nCr = \frac{n!}{r!(n-r)!}). Here, (n = 5) and (r = 2), so (5C2 = \frac{5!}{2!(5-2)!} = \frac{5!}{2! \cdot 3!} = \frac{5 \times 4}{2 \times 1} = 10). Thus, (5C2 = 10).
There are two sections in a question paper each contain five questions A students has to answer 6 questions?
he can choose the answer in this way, 5c1*5c3+5c2*5c2+5c3*5c1 evaluate, the answer will be 200.
Factor of 5C2 plus 3C-2?
(5c - 2)(c +1)
20 c4 3c3 5c2 is this a monomial?
No. A monomial cannot have the variable c to different powers.
What is the number of combinations for 2 out of 5 events?
There are 5C2 = 5*4/(2*1) = 10 combinations.
What is the probability of drawing two jacks and 3 tens of any suite from a standard deck of cards?
The probability of drawing two jacks and three tens of any suite from a standard deck of cards is: 5C2 ∙ (4/52)∙(3/51)∙(4/50)∙(3/49)∙(2/48) = 0.00000923446... ≈ 0.0009234% where 5C2 = 5!/[(5-2)!∙(2!)] = 10
What is 7 and 30 simplified?
7/30 cannot be simplified.7/30 cannot be simplified.7/30 cannot be simplified.7/30 cannot be simplified.
What is 15 over 13 simplified?
It can not be simplified further.
What is 128 over 165 simplified?
It is simplified.
Can 30 over 49 be simplified?
No it can not be simplified
What is 10.9 simplified?
10.9 cannot be simplified.
