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The expression (5c2) represents the number of combinations of 5 items taken 2 at a time. It can be calculated using the formula ( \frac{n!}{r!(n-r)!} ), where (n) is the total number of items and (r) is the number of items to choose. For (5c2), this equals ( \frac{5!}{2!(5-2)!} = \frac{5!}{2! \cdot 3!} = \frac{5 \times 4}{2 \times 1} = 10). Therefore, (5c2) simplifies to 10.
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Is c3-5c2-36c a trinomial?
Yes
What is the value of 5C2?
The value of (5C2) is calculated using the combination formula (nCr = \frac{n!}{r!(n-r)!}). Here, (n = 5) and (r = 2), so (5C2 = \frac{5!}{2!(5-2)!} = \frac{5!}{2! \cdot 3!} = \frac{5 \times 4}{2 \times 1} = 10). Thus, (5C2 = 10).
Factor of 5C2 plus 3C-2?
(5c - 2)(c +1)
What is the number of combinations for 2 out of 5 events?
There are 5C2 = 5*4/(2*1) = 10 combinations.
What is the probability of drawing two jacks and 3 tens of any suite from a standard deck of cards?
The probability of drawing two jacks and three tens of any suite from a standard deck of cards is: 5C2 ∙ (4/52)∙(3/51)∙(4/50)∙(3/49)∙(2/48) = 0.00000923446... ≈ 0.0009234% where 5C2 = 5!/[(5-2)!∙(2!)] = 10
Is c3-5c2-36c a trinomial?
Yes
What is the value of 5C2?
The value of (5C2) is calculated using the combination formula (nCr = \frac{n!}{r!(n-r)!}). Here, (n = 5) and (r = 2), so (5C2 = \frac{5!}{2!(5-2)!} = \frac{5!}{2! \cdot 3!} = \frac{5 \times 4}{2 \times 1} = 10). Thus, (5C2 = 10).
There are two sections in a question paper each contain five questions A students has to answer 6 questions?
he can choose the answer in this way, 5c1*5c3+5c2*5c2+5c3*5c1 evaluate, the answer will be 200.
Factor of 5C2 plus 3C-2?
(5c - 2)(c +1)
20 c4 3c3 5c2 is this a monomial?
No. A monomial cannot have the variable c to different powers.
What is the number of combinations for 2 out of 5 events?
There are 5C2 = 5*4/(2*1) = 10 combinations.
What is the probability of drawing two jacks and 3 tens of any suite from a standard deck of cards?
The probability of drawing two jacks and three tens of any suite from a standard deck of cards is: 5C2 ∙ (4/52)∙(3/51)∙(4/50)∙(3/49)∙(2/48) = 0.00000923446... ≈ 0.0009234% where 5C2 = 5!/[(5-2)!∙(2!)] = 10
What is 7 and 30 simplified?
7/30 cannot be simplified.7/30 cannot be simplified.7/30 cannot be simplified.7/30 cannot be simplified.
What is 15 over 13 simplified?
It can not be simplified further.
What is 116 over 15 simplified?
116/15 cannot be simplified further.116/15 cannot be simplified further.116/15 cannot be simplified further.116/15 cannot be simplified further.
Is three over four simplified?
3/4 cannot be simplified further.3/4 cannot be simplified further.3/4 cannot be simplified further.3/4 cannot be simplified further.
How do you simplify 115 twelfths?
115/12 cannot be simplified.115/12 cannot be simplified.115/12 cannot be simplified.115/12 cannot be simplified.
