5X - 30 = 3X + 2
subtract 3X from both sides
5X - 3X - 30 = 3X - 3X + 2
2X - 30 = 2
add 30 to each side
2X - 30 + 30 = 2 + 30
2X = 32
divide both sides integers by 2
(2/2)X = 32/2
X = 16
-----------------check in original equation
5(16) - 30 = 3(16) + 2
80 - 30 = 48 + 2
50 = 50
checks
3x + 2 = 3x + 6 This is not possible.
Their graphs are.
(2, -1)
3x + 2 = 0 3x = -2 x = -2/3
4x plus 7 plus 3x equals 19 plus xx = 2
3x + 2 = 3x + 6 This is not possible.
Their graphs are.
(2, -1)
3x + 2 = 0 3x = -2 x = -2/3
4x plus 7 plus 3x equals 19 plus xx = 2
3x + 2 = -10 3x = -12 x = -4
x = 7 and 2/3
3x + 2 = Y
(-2, 4)
x + 2 = 3x-1 -2x = -3x = 1,5
x+2) by Algebraica Long Division. x^(3) + 3x^(2) + 3x + 2 ) = x^(2) + x + 1 -x^(3)- 2x^(2) ¬ 0 + x^(2) + 3x 0 - x^(2) - 2x ¬ 0 + 0 + x + 2 0 + 0 - x - 2 ¬ = 0 Hence answer is x^)2) + x + 1 ( Thos does NOT factor .
x = 2