(6 × 2) + 3 = 15
6x2-2x+36 = 5x2+10x 6x2-5x2-2x-10x+36 = 0 x2-12x+36 = 0 (x-6)(x-6) = 0 x = 6 or x = 6 It has two equal roots.
When the given expression equals 0 then x = -1/6 and x = -6
6(x - 2)(x - 1)
9+6x2=21
6x2-18x+12 = (6x-6)(x-2)
(6 × 2) + 3 = 15
6x2 + 14x -12 = (3x - 2) (2x + 6). There they are.
6x2-2x+36 = 5x2+10x 6x2-5x2-2x-10x+36 = 0 x2-12x+36 = 0 (x-6)(x-6) = 0 x = 6 or x = 6 It has two equal roots.
When the given expression equals 0 then x = -1/6 and x = -6
34+(6*2)=34+12+46
6(x - 2)(x - 1)
9+6x2=21
x3 + 6x2 - 4x - 24 = (x + 6)(x2 - 4) = (x + 6)(x + 2)(x - 2)
x5+4x4-6x2+nx+2 when divided by x+2 has a remainder of 6 Using the remainder theorem: n = 2
6x2-9x-6 is equal to 66.
6x2=12 2x-28=?