The algebraic expression is 6x+k
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If: k+3=-3 Then: k=-3-3 k=-6
You don't need the q.f. That factors to (k + 6)(k - 1), so k = 1, -6 but if you insist... Plugging in the values for a, b and c leads us to (-5 plus or minus 7 times the square root of 1) divided by 2 (-5 + 7) ÷ 2 = 1 (-5 - 7) ÷ 2 = -6 but you knew that already. No the problem asked me to do it using the quadratic formula ...any way thanks
First, factor out the k. So, k(4+2) = 30 or 6k = 30 Then divide by 6. k = 30/6 = 5 So k = 5.
If: 6x^2 +2x +k = 0 has equal roots Then using the discriminant of b^2 -4ab=0: 4 -24k=0 => k=-4/-24 => k=1/6 Therefore the value of k = 1/6