-14
If: k+3=-3 Then: k=-3-3 k=-6
You don't need the q.f. That factors to (k + 6)(k - 1), so k = 1, -6 but if you insist... Plugging in the values for a, b and c leads us to (-5 plus or minus 7 times the square root of 1) divided by 2 (-5 + 7) ÷ 2 = 1 (-5 - 7) ÷ 2 = -6 but you knew that already. No the problem asked me to do it using the quadratic formula ...any way thanks
First, factor out the k. So, k(4+2) = 30 or 6k = 30 Then divide by 6. k = 30/6 = 5 So k = 5.
If: 6x^2 +2x +k = 0 has equal roots Then using the discriminant of b^2 -4ab=0: 4 -24k=0 => k=-4/-24 => k=1/6 Therefore the value of k = 1/6
The question - with the second alternative - is tautological (m = n).
-14
If: k+3=-3 Then: k=-3-3 k=-6
6 divided by the sum of 4 times x and 5 times k is equal to 6 times the reciprocal of (4x + 5k).
A number, k, increased by two and a half.
There is no answer, because "-10 + k + 2" is not a question. It's justa number, and the number that it is depends on what 'k' is.If the teacher said "Simplify (-10 + k + 2) .", then the response is " k - 8 ".But that's not the answer to " -10 + k + 2 ". It's the answer to "Simplify.".
xjdf kg k;ks
Kindergarten-6 grade in elementary-4 years in high school and PLUS 2 years in Senior High School. that is K plus 12
Algebraic expression 14 less than the quantity k times 6
You don't need the q.f. That factors to (k + 6)(k - 1), so k = 1, -6 but if you insist... Plugging in the values for a, b and c leads us to (-5 plus or minus 7 times the square root of 1) divided by 2 (-5 + 7) ÷ 2 = 1 (-5 - 7) ÷ 2 = -6 but you knew that already. No the problem asked me to do it using the quadratic formula ...any way thanks
k = 14/43
-12k - 96