114 base 6
64 different whole numbers can be written with 6 bits.
73 written in base 2 is... 1001001
64 written in base 2 is 1000000
You can't - unless you're including using bases other than base 10. In base 3, the number 6 (2x3) is written as 20.
8 written in base 5 is 13; 1*5 + 3*1 = 8 similarly 8 written in base 6 is 12; 1*6 + 2*1
114 base 6
64 different whole numbers can be written with 6 bits.
11000 in base 2 is 24 in decimal. 110 in base 2 is 6 in decimal. 24 - 6 is 18. In base 2 18 is 10010.
200 (base 6) is 2 x 6^2 + 0 x 6^1 + 0 x 6^0 = 2 x 36(base 10) = 72 (base 10).
73 written in base 2 is... 1001001
64 written in base 2 is 1000000
I would convert to base 10 , multiply and then convert back to base 6. 35 base 6 is 3 * 6 + 5 = 23 in base ten. 4 * 23 = 92 which is 2*36 + 3* 6 + 2 , in base 6 , the answer is 232 .
You can't - unless you're including using bases other than base 10. In base 3, the number 6 (2x3) is written as 20.
2³, I believe.
Yes, 6 is the base and 2 is the exponent in 6^2. To solve, 6 * 6 = 36 since we know that an exponent is not, in this instance, 6 * 2, but 6 * 6. If it was 6^3, the answer would be 6 * 6 * 6 = 216.
it is the like 2^3 +2^4 in that 2 is the base it is written like 342