6y + (2-2)y = 6y 6(5) + (2-2)5 = 6(5) 30 + 0 = 30
y = -1
12y + 2 or 2*(6y+ 1)
The slope of -x plus 6y is equals to 12 is said to be (2 + 1/6x).
Equation of circle: x^2 +4x +y^2 +6y -17 = 0 Completing the squares: (x+2)^2 +(y+3)^2 = 30 which is the radius squared Area of the circle: 30*pi square units
16 = 6y +2 Yes
(2, 1)
6y + (2-2)y = 6y 6(5) + (2-2)5 = 6(5) 30 + 0 = 30
y = -1
12y + 2 or 2*(6y+ 1)
The slope of -x plus 6y is equals to 12 is said to be (2 + 1/6x).
Equation of circle: x^2 +4x +y^2 +6y -17 = 0 Completing the squares: (x+2)^2 +(y+3)^2 = 30 which is the radius squared Area of the circle: 30*pi square units
yes it is!
Rearrange the equations in the form of:- 6x-6y = 17-11 -4x+6y = 21 6x-6y = 6 -4x+6y = 21 Add both equatios together in order to eliminate y: 2x = 27 Divide both sides by 2: x = 13.5 Substitute the value of x into the equations to find the value of y: x = 13.5 and y = 12.5
(4, -2)
5y - 2 + y + 52 = 6y + 50 - 3y6y + 50 = 9y + 50y = 0
By definition: 4y-2 = 6y+8 4y-6y = 8+2 -2y = 10 y = -5 and by substituting this value into the equation x = -22