Q: What is the slope of -x plus 6y 12?

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3x + 6y = 12 Rearranging terms: 6y = -3x + 12 Divide through by 6: y = -1/2*x + 2

y = -(2/3)x -2

It is a straight line equation and can be rearranged into slope intercept form as follows:- 6x-6y = 12 -6y = -6x+12 y = x-2 which is now in slope intercept form

If 10x + 6y = 24, y = (24 - 10x)/6 = 4 - (5/3)x. The slope of a line with an equation written in this format is the coefficient of x, therefore -(5/3).

x - 3y = -3: multiply by -2 giving -2x + 6y = 6, but -2x + 6y = 12 so we have a problem! Misprint?

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3x + 6y = 12 Rearranging terms: 6y = -3x + 12 Divide through by 6: y = -1/2*x + 2

y = -(2/3)x -2

-5x + 6y = 24 6y = 5x + 24 y = 5/6 x + 4 the slope is 5 6

3x-6y=12; subtract 12 & add 6y to both sides 3x-12=6y; divide by 6 (1/2)x-2=y; re-write y=(1/2)x-2 slope intercept form

It is a straight line equation and can be rearranged into slope intercept form as follows:- 6x-6y = 12 -6y = -6x+12 y = x-2 which is now in slope intercept form

x + 2y = 62y = -x + 6y = -1/2 x + 3

If 10x + 6y = 24, y = (24 - 10x)/6 = 4 - (5/3)x. The slope of a line with an equation written in this format is the coefficient of x, therefore -(5/3).

If the equation is 6y - 3x - 2 = 0 6y - 3x - 2 = 0 6y = 3x + 2 y = (1/2)x + 2 The slope is 1/2. If the equation is 6y = -3x - 2 y = -(1/2)x - 2 The slope is -1/2.

Solving these simultaneous equations by the elimination method:- x = 1/8 and y = 23/12

x - 3y = -3: multiply by -2 giving -2x + 6y = 6, but -2x + 6y = 12 so we have a problem! Misprint?

You can find the slope of a line by rearranging it in the format y = s(x + a) + b. In that case, "s" will be the slope: 3x - 6y = 15 6y = 3x - 15 2y = x - 5 y = x/2 - 2.5 So the slope in this case is 1/2.

First, you need to find the slope of the line we're given: 2x = 12y + 4 ∴ x = 6y + 3 ∴ 6y = x - 3 ∴ y = x/6 - 3 By that we can see that the slope of the line given is 1/6. To find the slope that is perpendicular, all you need to do reverse that fraction. Instead of 1/6, it would be 6/1. So the answer to your question is 6.