25y2 - 49w2 = (5y)2 - (7w)2 = (5y - 7w)(5y + 7w)
whats w stand for? -7w + 3(w+2)= -14
Let's start with making the variables coefficient a positive number. This obtained by simply multiply the negative fraction by -1/1, which results in the same fraction just positive. However, what you do to one side you must always do to the other. -2/7w = 8 -1/1 x -2/7w = 8 x -1/1 = 2/7w = -8 Now we see that our variable is still attached to the coefficient by means of multiplication. We must perform the inverse operation to detach the variable. In our case, division will suffice. 2/7w ÷ 2/7 = -8 ÷ 2/7 1/w = -8 ÷ 2/7 1/w = -28 w = -1/28. Is it (-2 over 7)w or -2 over (7w)?
t
56w2 + 17w - 3 = 56w2 + 24w - 7w - 3 = 8w(7w + 3) - 1(7w + 3) = (7w + 3)(8w - 1)
25y2 - 49w2 = (5y)2 - (7w)2 = (5y - 7w)(5y + 7w)
whats w stand for? -7w + 3(w+2)= -14
-63=7w
16
Ill assume you mean for an are of a rectangle. w will stand for width. So you know the equation for a rectangle is L*W, so if length is 7W, then the area is 7W*W=Area or 7W^2
Let's start with making the variables coefficient a positive number. This obtained by simply multiply the negative fraction by -1/1, which results in the same fraction just positive. However, what you do to one side you must always do to the other. -2/7w = 8 -1/1 x -2/7w = 8 x -1/1 = 2/7w = -8 Now we see that our variable is still attached to the coefficient by means of multiplication. We must perform the inverse operation to detach the variable. In our case, division will suffice. 2/7w ÷ 2/7 = -8 ÷ 2/7 1/w = -8 ÷ 2/7 1/w = -28 w = -1/28. Is it (-2 over 7)w or -2 over (7w)?
t
56w2 + 17w - 3 = 56w2 + 24w - 7w - 3 = 8w(7w + 3) - 1(7w + 3) = (7w + 3)(8w - 1)
4w - 2 = -7w11w - 2 = 011w = 2w = 2/11
127w = 847w/7 = 84/7w = 12
7w + 2 = 3w + 94 Subtract 3w from both sides: 4w + 2 = 94 Subtract 2 from both sides: 4w = 92 Divide both sides by 4: w = 23
7w - 4w - 6w = (7 - 4 - 6)w = -3w