Solve one of the formulas for A, then substitute that into the other formula to solve for B, then substitute the solution for B into one of the formulas to solve for A. Here is how: Givens: A+B=8 A-B=9 So: If A+B=8 then A=8-B Next, substitute this into the other formula... A-B=9 (8-B)-B=9 (-B) - B = 1 (-2B) = 1 B= (- 1/2) Next, substitute the solution for B into one of the formulas to solve for A.... A+B=8 A+ (-1/2) = 8 A = 8 and 1/2 So... B= (- 1/2) A = 8 and 1/2
Given:a + b = 2a - b = 8Then:a = b + 8∴ (b + 8) + b = 2∴ 2b = -6∴ b = -3∴ a = 5
(b + 8)(b - 1)
5b = 8 b = 8/5 or 1.6
b - 8
The sum of b and 8 would be written b+8 or 8+b(commutative property of addition)
The equation for the perimeter of a rectangle is 2(a+b) where a is the length of the short side and b is the length of the long side. In this case 2(a+b)=18, so a+b=9 keeping in mind that a has to be shorter than b (to be the short side), the possible answers to this are: a=1, b=8 a=2, b=7 a=3, b=6 a=4, b=5
-b = 8 multiply each side by -1 b = -8
Solve one of the formulas for A, then substitute that into the other formula to solve for B, then substitute the solution for B into one of the formulas to solve for A. Here is how: Givens: A+B=8 A-B=9 So: If A+B=8 then A=8-B Next, substitute this into the other formula... A-B=9 (8-B)-B=9 (-B) - B = 1 (-2B) = 1 B= (- 1/2) Next, substitute the solution for B into one of the formulas to solve for A.... A+B=8 A+ (-1/2) = 8 A = 8 and 1/2 So... B= (- 1/2) A = 8 and 1/2
8 bits in a byte
5b = 8 therefore b = 8/5 therefore b = 1.6
Given:a + b = 2a - b = 8Then:a = b + 8∴ (b + 8) + b = 2∴ 2b = -6∴ b = -3∴ a = 5
You can abbreviate "bytes" with a capital B. Try not to confuse this with a lowercase b, which is short for "bits".
The expression is: b/8
-8 + b = 4 add 8 to both sides: b = 12
-8
(b + 8)(b - 1)