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If f of x equals x plus 1 and g of f of x equals x what is g of x?
f(x)=x+1 g(f(x))=x f(x)-1=x g(x)=x-1
What is the integral of the quantity f prime times g minus f times g prime divided by the quantity f squared plus g squared with respect to x where f and g are functions of x?
∫ [f'(x)g(x) - f(x)g'(x)]/(f(x)2 + g(x)2) dx = arctan(f(x)/g(x)) + C C is the constant of integration.
If hx equals f o g x and hx equals sqrt x plus 5 find gx if fx equals sqrt x plus 2?
g(x) = x + 3 Then f o g (x) = f(g(x)) = f(x + 3) = sqrt[(x+3) + 2] = sqrt(x + 5)
What is the derivative of f plus g of 3 and f times g of 3 given that f of 3 equals 5 d dx f of 3 equals 1.1 g of 3 equals -4 d dx g of 3 equals 7 Also please explain QUICK THANK YOU?
d/dx [f(x) + g(x)] = d/dx [f(x)] + d/dx [g(x)] or f'(x) + g'(x) when x = 3, d/dx [f(x) + g(x)] = f'(3) + g'(3) = 1.1 + 7 = 8.1 d/dx [f(x)*g(x)] = f(x)*d/dx[g(x)] + d/dx[f(x)]*g(x) when x = 3, d/dx [f(x)*g(x)] = f(3)*g'(3) + f'(3)*g(3) = 5*7 + 1.1*(-4) = 35 - 4.4 = 31.1
Finf f prime x and g prime x if f x equals sin of 1 over x and g x equals 1 over sin x?
f(x)= sin(1/x) and g(x)=1/sin(x) [u(v)]' = u'(v) * v', where u and v are functions So f'(x) = sin'(1/x) * (1/x)' = cos(x) * (-1/x2) = -cos(x)/x2 g'(x) = (1/x)' applied to sin(x) * (sin(x))' = -1/(sin2(x)) * cos(x) = -cos(x)/(sin2(x))
If c varies jointly as f and g and c equals 27 and f equals 18 and g equals 6 find c when f equals 30 and g equals 10?
x = 75
F varies jointly as g h and j One set of values is f equals 18 g equals 4 h equals 3 and j equals 5 Find f when g equals 5 h equals 12 and j equals 3?
f = 54
What conditions need to hold for two functions f and g to be equal?
The values of f and g are equal at each point in the domainThe domains of f and g are equal
When f of g of x equals x?
f and g are inverse functions.
If f of x equals x plus 1 and g of f of x equals x what is g of x?
f(x)=x+1 g(f(x))=x f(x)-1=x g(x)=x-1
Assume f of x equals 4x plus 8 and g of x equals 5 What is the value of g o f-1?
g(x) = 5. So whatever f(x) or f(-1) is, g of that is going to be 5.
What is the integral of the quantity f prime times g minus f times g prime divided by the quantity f squared plus g squared with respect to x where f and g are functions of x?
∫ [f'(x)g(x) - f(x)g'(x)]/(f(x)2 + g(x)2) dx = arctan(f(x)/g(x)) + C C is the constant of integration.
What is the integral of the quantity f prime times g minus f times g prime divided by the quantity f squared minus g squared with respect to x where f and g are functions of x?
∫ [f'(x)g(x) - f(x)g'(x)]/(f(x)2 - g(x)2) dx = (1/2)ln[(f(x) - g(x))/(f(x) + g(x))] + C
What are the notes to 'Defying Gravity' in 'Wicked'?
C-prime is the dominant note in the song "Defying Gravity" in the musical "Wicked."Specifically, two stanzas are Elphaba's contributions to "Defying Gravity" in "Wicked." The notes of the first stanza are the same as those of the second. The following lists the notes sung by Elphaba in each of her two stanzas on the soundtrack of the original Broadway cast:C-prime, d-prime, f-prime (5 in succession), g-prime;C-prime, d-prime, f-prime (3), g-prime (2);A-prime (2), g-prime, f-prime, e-prime, f-prime, d-double prime (2), c-double prime;C-prime, b flat-prime, a-prime, g-prime, f-prime;C-prime, b flat-prime, a-prime, g-prime, f-prime, e-prime, d-prime;C-prime, b, c-prime, b, c-prime, g-prime, c-prime, c-prime, g;C-prime, b, c-prime, a, g (2);C-prime, b, c-prime, g-prime, c-prime, b, c-prime, c-double prime, b-prime, g-prime, c-prime (2), d-prime (2), c-prime;E-prime (3), d-prime, c-prime, g, c-prime;E-prime (2), d-prime, c-prime, b, g, a-prime, g-prime.
If hx equals f o g x and hx equals sqrt x plus 5 find gx if fx equals sqrt x plus 2?
g(x) = x + 3 Then f o g (x) = f(g(x)) = f(x + 3) = sqrt[(x+3) + 2] = sqrt(x + 5)
What is the domain of the function G of F of x when F of x equals 8 minus x G of y equals square root of y G of F of x equals square root of 8 minus x?
x
What is the derivative of f plus g of 3 and f times g of 3 given that f of 3 equals 5 d dx f of 3 equals 1.1 g of 3 equals -4 d dx g of 3 equals 7 Also please explain QUICK THANK YOU?
d/dx [f(x) + g(x)] = d/dx [f(x)] + d/dx [g(x)] or f'(x) + g'(x) when x = 3, d/dx [f(x) + g(x)] = f'(3) + g'(3) = 1.1 + 7 = 8.1 d/dx [f(x)*g(x)] = f(x)*d/dx[g(x)] + d/dx[f(x)]*g(x) when x = 3, d/dx [f(x)*g(x)] = f(3)*g'(3) + f'(3)*g(3) = 5*7 + 1.1*(-4) = 35 - 4.4 = 31.1
