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Q: What is 9 times 8 with the digits reversed?
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A two digit number is five times the sum of the digits if 9 is added to the number the digits are reversed find the number?

45


There is a number that is 9 times the sum of its digits what is this number?

81 8+1=9 9*9=81


How do you know if a number is in the 9 times table?

if you add the digits of the number such as 81 8+1=9 every time, the digits of the number will add up to 9


The sum of the digits in a two digit number is 9 if the digits are reversed the new number will be 9 less than the original?

78 Good guess, but 7 + 8 = 15, not 9; so that answer is incorrect. The correct answer is 54. 5 + 4 = 9 45 is 9 less than 54. * * * * * If the sum of the digits of a 2-digit number is 9, and if the order of the digits is reversed the new number will be a multiple of 9 different from the original. It could be bigger or smaller, and the difference could be 18 or 27. For example, 7+2 = 9 and 72 -27 = 45 (which is not 9 but a multiple of 9)


A certain two-digit number is equal to 9 times the sum of its digitIf 63 were subtracted from the number the digits would be reversed Find the number?

81.


What is the missing number 6 3 81 9 7 36 4 4 61 8 42?

Answer 633 The sequence is formed by reversing the digits forming the product of the two previous numbers. 6 x 3 = 18 (reversed is 81) 9 x 7 = 63 (reversed is 36) 4 x 4 = 16 (reversed is 61) 8 x 42 = 336 (reversed is 633


What is the missing number in the sequence 9-61-52-63-94- - 18?

46. It's the square numbers with their digits reversed: 9 → 9 = 32 61 → 16 = 42 52 → 25 = 52 63 → 36 = 62 94 → 49 = 72 ??? 18 → 81 = 92 The missing number is the square of 8 with its digits reversed: 82 = 64 → 46.


Number that is 2 times the sum of its digits?

18 1+8=9 9x2=18


How many 9 digit combinations are there for the numbers 1 through 9?

9 times 9 times 9 times 9 times 9 times 9 times 9 times 9 times 9 = Imagine it's a combination lock with 9 tumblers. Each tumbler has 9 "positions" - the digits from 1 to 9. So you multiply the number of digits [9] against itself [9] for as many tumblers are in the combination (9). Tumbler # 1 2 3 4 5 6 7 8 9 Number of possible digits 9 9 9 9 9 9 9 9 9


The divisibility rules of the 1st 10 powers of 5?

5: The number ends in 0 or 5 25: The number ends in 00, 25, 50 or 75 125: The number ends in 000, 125, 250, 375, 500, 625, 750 or 875 625: The last 4 digits are a multiple of 625 The 1,000s digit is 0 or 5 and the last 3 digits are 000 or 625 The 1,000s digit is 1 or 6 and the last 3 digits are 250 or 875 The 1,000s digit is 2 or 7 and the last 3 digits are 500 The 1,000s digit is 3 or 8 and the last 3 digits are 125 or 750 The 1,000s digit is 4 or 9 and the last 3 digits are 375 3,125: The last 5 digits are a multiple of 3,125 The 10,000s digit is 0 or 5 and the last 4 digits are a multiple of 3,125 The 10,000s digit is 1 or 6 and the last 4 digits are 625 times a number that ends in 4 or 9 The 10,000s digit is 2 or 7 and the last 4 digits are 625 times a number that ends in 3 or 8 The 10,000s digit is 3 or 8 and the last 4 digits are 625 times a number that ends in 2 or 7 The 10,000s digit is 4 or 9 and the last 4 digits are 625 times a number that ends in 1 or 6 15,625: The last 6 digits are a multiple of 15,625 The 100,000s digit is 0 or 5 and the last 5 digits are a multiple of 15,625 The 100,000s digit is 1 or 6 and the last 5 digits are 3,125 times a number that ends in 3 or 8 The 100,000s digit is 2 or 7 and the last 5 digits are 3,125 times a number that ends in 1 or 6 The 100,000s digit is 3 or 8 and the last 5 digits are 3,125 times a number that ends in 4 or 9 The 100,000s digit is 4 or 9 and the last 5 digits are 3,125 times a number that ends in 2 or 7 78,125: The last 7 digits are a multiple of 78,125 The 1,000,000s digit is 0 or 5 and the last 6 digits are a multiple of 78,125 The 1,000,000s digit is 1 or 6 and the last 6 digits are 15,625 times a number that ends in 1 or 6 The 1,000,000s digit is 2 or 7 and the last 6 digits are 15,625 times a number that ends in 2 or 7 The 1,000,000s digit is 3 or 8 and the last 6 digits are 15,625 times a number that ends in 3 or 8 The 1,000,000s digit is 4 or 9 and the last 6 digits are 15,625 times a number that ends in 4 or 9 390,625: The last 8 digits are a multiple of 390,625 The 10,000,000s digit is 0 or 5 and the last 7 digits are a multiple of 390,625 The 10,000,000s digit is 1 or 6 and the last 7 digits are 78,125 times a number that ends in 2 or 7 The 10,000,000s digit is 2 or 7 and the last 7 digits are 78,125 times a number that ends in 4 or 9 The 10,000,000s digit is 3 or 8 and the last 7 digits are 78,125 times a number that ends in 1 or 6 The 10,000,000s digit is 4 or 9 and the last 7 digits are 78,125 rimes a number that ends in 3 or 8 1,953,125: The last 9 digits are a multiple of 1,953,125 The 100,000,000s digit is 0 or 5 and the last 8 digits are a multiple of 1,953,125 The 100,000,000s digit is 1 or 6 and the last 8 digits are 390,625 times a number that ends in 4 or 9 The 100,000,000s digit is 2 or 7 and the last 8 digits are 390,625 times a number that ends in 3 or 8 The 100,000,000s digit is 3 or 8 and the last 8 digits are 390,625 times a number that ends in 2 or 7 The 100,000,000s digit is 4 or 9 and the last 8 digits are 390,625 times a number that ends in 1 or 6 9,765,625: The last 10 digits are a multiple of 9,765,625 The 1,000,000,000s digit is 0 or 5 and the last 9 digits are a multiple of 9,765,625 The 1,000,000,000s digit is 1 or 6 and the last 9 digits are 1,953,125 times a number that ends in 3 or 8 The 1,000,000,000s digit is 2 or 7 and the last 9 digits are 1,953,125 times a number that ends in 1 or 6 The 1,000,000,000s digit is 3 or 8 and the last 9 digits are 1,953,125 times a number that ends in 4 or 9 The 1,000,000,000s digit is 4 or 9 and the last 9 digits are 1,953,125 times a number that ends in 2 or 7


A man is 25 years old and his wife is 23 when will the sum of their ages be 8 times as much of the sum of their digits added and when will it be 9 times the sum of their digits?

Eight times when they are 73 and 71; nine times when they are 80 and 78.


How do you learn your 7 8 and 9 times tables in one day?

Repeat, repeat, repeat. The 9's table is probably the easiest of them because of the pattern of the answers1 times 9 is 9.2 times 9 is 18. The digits 1 and 8 add up to 9.3 times 9 is 27. The digits 2 and 7 add up to 9.4 times 9 is 36. The digits 3 and 6 add up to 9.5 times 9 is 45. the same all the way down, forever6 times 9 is 54.7 times 9 is 63.8 times 9 is 72.9 times 9 is 81.10 times 9 is 90.11 times 9 is 99.12 times 9 is 108.Notice first that all of the answers have digits that add up to 9. 18 is 1 and 8, 27 is 2 and 7, 36 is 3 and 6. For every single whole number that is a multiple of 9, this pattern holds, no matter how big the number is!For 2 times 9 through to 9 times 9, notice the pattern:For 2 times 9, the answer begins with 1, and the other digit has to be 8: 18The answer begins with the multiplier (2) minus 1.For 3 times 9, it is the same. The answer begins with 2, so the second digit has to be 7.For 4 times 9, same thing... 36They're all following the same pattern. First digit is the multiplier minus one, and the second digit is what's needed for the digits to add to 9.The only ones you need to remember are10 times 9, which isn't hard11 times 9, which isn't hard12 times 9, which is 108, and you might have to work on that a little.So you know the 9's table with almost no effort. You just have to spend time repeating the 7's and 8's.