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Q: What is 9 times 8 with the digits reversed?
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The sum of the digits in a two digit number is 9 if the digits are reversed the new number will be 9 less than the original?

78 Good guess, but 7 + 8 = 15, not 9; so that answer is incorrect. The correct answer is 54. 5 + 4 = 9 45 is 9 less than 54. * * * * * If the sum of the digits of a 2-digit number is 9, and if the order of the digits is reversed the new number will be a multiple of 9 different from the original. It could be bigger or smaller, and the difference could be 18 or 27. For example, 7+2 = 9 and 72 -27 = 45 (which is not 9 but a multiple of 9)


A certain two-digit number is equal to 9 times the sum of its digitIf 63 were subtracted from the number the digits would be reversed Find the number?

81.


What is the missing number 6 3 81 9 7 36 4 4 61 8 42?

Answer 633 The sequence is formed by reversing the digits forming the product of the two previous numbers. 6 x 3 = 18 (reversed is 81) 9 x 7 = 63 (reversed is 36) 4 x 4 = 16 (reversed is 61) 8 x 42 = 336 (reversed is 633


Find a base 7 three digit number which has its digits reversed when expressed in base 9?

5037 = 248 = 3059


Given the digits 0-9... how many ways can you form an even number without replacement of numbers?

one digit: 5 ways two digits: 5 * 9 ways three digits: 5 * 9 * 8 ways four digits: 5 * 9 * 8 * 7 ways ... ten digits: 5 * 9! ways So if you have to use ten digits, then the answer is 5 * 9! = 1814400. If you can use anywhere from one to ten digits, then the answer is: 5 * (9! + 8! + 7! + 6! + 5! + 4! + 3! + 2! + 1) = 2045565