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How do you solve a to the 3rd power plus b to the 3rd power divided by a plus b?
(a3 + b3)/(a + b) = (a + b)*(a2 - ab + b2)/(a + b) = (a2 - ab + b2)
Is x to the -1 power the same as 1 divided by x?
Yes. In general, a negative power can be defined as follows: a-b = 1 / ab.
What is the answer to x-ab?
x-ab=0 x=ab
How do you make a the subject of r equals ab divided by a plus b?
Are you asking to have that equation solved for 'a' ?r = ab / (a + b)Multiply each side by (a + b) . . . ra + rb = abSubtract 'ra' from each side. . . . rb = ab - raFactor the right side . . . . . . . . . rb = a (b - r)Divide each side by (b - r) . . . . . a = rb / (b - r)
How many ways can you arrange 5 items if two have to be next to each other?
There are 48 possibilities where 2 of 5 items must be adjacent.If you have 5 items, and they can be arranged in any order, there are 1205 x 4 x 3 x 2 ways to arrange them, for example ABCDE, ABCED, and so forth.However, if any two need to be placed next to each other, the number of variations is reduced to [4 x 3 x 2] x2 (=48), where there are only 4 separate "units" arranged, but the double-unit can appear with either of the pair first.For example, if A and B must be together, you have 24 possibilities:(AB)CDE(AB)CED(AB)DCE(AB)DEC(AB)EDC(AB)ECDC(AB)DEC(AB)EDD(AB)CED(AB)ECE(AB)CDE(AB)DCCD(AB)EDC(AB)ECE(AB)DEC(AB)DDE(AB)CED(AB)CCDE(AB)CED(AB)DEC(AB)DCE(AB)EDC(AB)ECD(AB)and another 24 where (AB) is replaced by (BA).
