AB/8C
as divided by 8/A can be reversed to multiplied by A/8
so B/C x A/8 = AB/8C
Example: If A=4 B=6 C=3
then 6/3 divided by 8/4 = 2/2 = 1
also AB/8C = 24/24 = 1
Q.E.D.
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67 plus 13 = 80 80 divided by 8 = 10
c equals b over 8
As A/B=C/D , So B=(A*D)/C
No. is it not a, b,c, or d.
In a right triangle, the right angle is formed by sides a and b. Side c is the hypotenuse.Theta is the interior angle that joins (let's say) sides b and c. The sin of theta is the length of a over the length of c. The cos of theta is the length of b over the length of c. The tan of theta is the length of a over the length of b.Sin theta= opposite divided by hypotenuse. Cos theta=adjacent divided by hypotenuse. Tan theta=opposite over adjacent.(Sin1-Cos1)-Tan1=-1.25623905Sorry, that was a mathematician's joke.