I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?
fx=3x-5 f=(3x-5)/x f2=(6x-10)/x /=divide
-3x + 1
(-3x - 1)(3x - 7)
5x-3x+x+8 = 2x+1+x+x 3x+8 = 4x+1 3x-4x = 1-8 -x = -7 x=7 Hope that helps.
17
B- It is a many-to-one function
please elaborate your question
I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?
9x2 + 6x + 1 = 9x2 + 3x + 3x + 1 = 3x(3x + 1) + 1(3x + 1) = (3x + 1)(3x + 1) or (3x +1)2
y = 3x + 2x^2 + k where k is any number
3x + 11
fx=3x-5 f=(3x-5)/x f2=(6x-10)/x /=divide
If that's -9x^3 - 3x^2 + 3x + 1, that factors to (1 - 3x^2)(1 + 3x)
2x2 + 3x + 1 = (x + 1)(2x + 1)
-3x + 1
At x = 3, the value of F(x) = 3x + 2 is the value 11, which graphs to the point (3, 11).