Given a data series, sampled at ƒk = 1/T, T being the sampling period of our data, for each frequency bin we can define the following:
Q = ƒk / δƒk
The equation you gave, 2y+5 = (x-4)2 can also be expressed as y = 0.5(x-4)2 - 5. In the form a(x-p)2 + q, the vertex is the point (p, q). Thus, the vertex of 2y + 5 = (x-4)2 is (4, -5).
Yes.
x2 + 13x + 4 = (x + 6½ + √38¼)(x + 6½ - √38¼). To find this, we need to find p and q, where p + q = 13, pq = 4. 4 = 42¼ - 38¼ = (6½ + √38¼)(6½ - √38¼); thus, p = (6½ + √38¼), q = (6½ - √38¼).
1750 2 x 5p x q where p and q are prime numbers. 2 * 5^p * q where p = 3 and q = 7
Yes. If one matrix is p*q and another is r*s then they can be multiplied if and only if q = r and, in that case, the result is a p*s matrix.
4 x q=
1 quarter = 25 x (1) cents 2 quarters = 25 x (2) cents 3 quarters = 25 x (3) cents 4 quarters = 25 x (4) cents . . . 'q' quarters = 25 x (q) cents
q5 x q-2 x q
Suppose that for any pair of numbers x and y, gcf(x, y) = g then x = g*p and y = g*q for some integers p and q. Therefore x + y = g*p + g*q = g*(p+q).
If x is 4 then 34.5x evaluates to 34.5 times 4 = 138
PQR P=2 Q=4 R=5 2 x 4 x 5 = 40
40.A 2 3 4 x 42 3 4 5 x 43 4 5 6 x 44 5 6 7 x 45 6 7 8 x 46 7 8 9 x 47 8 9 10 x 48 9 10 J x 49 10 J Q x 410 J Q K x 4J Q K A x 4
To find p(x) / q(x), we first need to substitute the expressions for p(x) and q(x) into the formula. So, p(x) = 20x^5 - 20x^4 + 24x^2 and q(x) = 4x^2. Therefore, p(x) / q(x) = (20x^5 - 20x^4 + 24x^2) / 4x^2. Simplifying this expression, we get 5x^3 - 5x^2 + 6.
The equation you gave, 2y+5 = (x-4)2 can also be expressed as y = 0.5(x-4)2 - 5. In the form a(x-p)2 + q, the vertex is the point (p, q). Thus, the vertex of 2y + 5 = (x-4)2 is (4, -5).
-2
Consider have x^(p/q) where the base, x, is a whole number. p and q are also whole numbers (q is not 0) so that the exponent, p/q, is a fraction. Then x^(p/q) = (x^p)^(1/q), that is, the qth root of x^p or equivalently, x^(p/q) = [x^(1/q)]^p, that is, the pth power of the qth root of x. For example, 64^(2/3) = 3rd root of 64^2 = 3rd [cube] root of 4096 = 16 or (cube root of 64)^2 = 4^2 = 16. If p/q is negative, the answer is the reciprocal of the answer obtained with positive p/q.
For the denominator, multiply the denominators together. For the numerator, subtract the second numerator multiplied by the first denominator from the first numerator multiplied by the second denominator: a/b - p/q = (a x q - b x p)/b x q eg: 6/7 - 3/4 = (6 x 4 - 7 x 3)/7 x 4 = (24 - 21)/28 = 3/28