The equation you gave, 2y+5 = (x-4)2 can also be expressed as y = 0.5(x-4)2 - 5. In the form a(x-p)2 + q, the vertex is the point (p, q). Thus, the vertex of 2y + 5 = (x-4)2 is (4, -5).
The vertex is at the point (0, 4).
2
All the time
y = 3x2+2x-1 Line of symmetry: x = -1/3 Vertex coordinate: (-1/3, -4/3)
(-3, -5)
(1/2, 71 and 3/4)or(0.5, 71.75)
The minimum value of the parabola is at the point (-1/3, -4/3)
The vertex is at the point (0, 4).
2
All the time
y = 3x2+2x-1 Line of symmetry: x = -1/3 Vertex coordinate: (-1/3, -4/3)
(-3, -5)
Question can be taken as multiple meanings. Please see discussion.
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The centre is (-5, 3)
X=1
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