answersLogoWhite

0


Best Answer

Some special cases that are relevant in practice are:

(a + b)2 = a2 + 2ab + b2

(a - b)2 = a2 - 2ab + b2

(x + a)(x + b) = x2 + (a+b)x + ab

User Avatar

Wiki User

10y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is Special Case Product of Binomial?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

Special cases of the product of trinomial and binomial?

(w - 1)2


How can you introduce squaring a binomial to the learners?

You could start with multiplying two different binomials ("FOIL" and such), then squaring a binomial is just a special case. In both cases, you could give a geometric illustration (a square with sides a+b and c+d, and the product represented by area)


Why is it that the product of sum is binomial?

It depends on the product of sum of what.


Is it possible to have two terms in the product when a binomial is squared?

...


What is the product of a binomial and its conjugate pair called as in vocabulary?

The answer depends on the level of mathematics. With complex numbers, it is the squared magnitude of the binomial.


Is it possible to have two terms in the product when any binomial is square?

No, it is not.


How do you write two binomials such that the product is equal to zero when x equals 3 or -5?

8


Can you give me 5 example of product of two binomials?

no please give me 5 riddles about product of 2 binomial


When is the product of two binomials also a binomial?

(a-b) (a+b) = a2+b2


How would you know if a binomial is a factor of a given product?

use long division.


What are the different special product formulas?

1. Square of a binomial (a+b)^2 = a^2 + 2ab + b^2 carry the signs as you solve 2. Square of a Trinomial (a+b+c)^2 = a^2 + b^2 + c^2 + 2ab + 2ac + 2bc carry the sings as you solve 3. Cube of a Binomial (a+b)^3 = a^3 + 3(a^2)b + 3a(b^2) + b^3 4. Product of sum and difference (a+b)(a-b) = a^2 - b^2 5. Product of a binomial and a special multinomial (a+b)(a^2 - ab + b^2) = a^3-b^3 (a-b)(a^2 + ab + b^2) = a^3-b^3


Is the third term in a factorable trinomial equal to the product of the constants in its binomial factors?

Yes it is