the distance between two points is length
The points where the vertical distance from the origin is twice the horizontal distance can be represented by the equation ( y = 2x ) and ( y = -2x ). This means for any point ((x, y)) on these lines, the absolute value of (y) is twice the absolute value of (x). Therefore, points such as ((1, 2)), ((2, 4)), ((-1, -2)), and ((-2, -4)) satisfy this condition.
Points: (2, 2) and (8, -6) Distance: 10
To find the distance between the points (-2, 5) and (-2, 0), we can use the distance formula. Since both points have the same x-coordinate (-2), the distance is simply the difference in their y-coordinates: |5 - 0| = 5. Therefore, the distance between the two points is 5 units.
If you mean points of (-4, 2) and (1, 2) then the distance works out as 5
In 2-dimensional space, it is the difference between their y-coordinates, in 3-dimensional space, it is the difference between their z-coordinates.
the distance between two points is length
The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (4) and a vertical distance y2-y1 (4). The square root of the squares is sqrt [42 + 42] = sqrt [32] = approx 5.66
11 points
Points: (-6, 1) and (-2, -2) Distance: 5 units
Points: (2, 2) and (8, -6) Distance: 10
To find the distance between the points (-2, 5) and (-2, 0), we can use the distance formula. Since both points have the same x-coordinate (-2), the distance is simply the difference in their y-coordinates: |5 - 0| = 5. Therefore, the distance between the two points is 5 units.
length
the distance between 2 points
The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (-6) and a vertical distance y2-y1 (8). The square root of the squares is sqrt [62 + 82] = sqrt [100] = 10.
If you mean points of (-4, 2) and (1, 2) then the distance works out as 5
Points: (2, 4) and (5, 0) Distance: 5