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The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (-6) and a vertical distance y2-y1 (8). The square root of the squares is sqrt [62 + 82] = sqrt [100] = 10.
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Find the distance between the points A 9 3 and B 15 11?
10
What is the distance between the points (10 12) and (4 36)?
The distance between points can be calculated using Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((4 - 10)² + (36 - 12)²) → distance = √((-6)² + (24)²) → distance = √(36 + 576) → distance = √612 → distance = 6 √17 ≈ 24.74 units.
What is the distance between the two points 2 3 and 3 0?
We use the distance formula to find the distance between the points (2,3) and (3,0) The distance is Square root of ((3^2+(2-3)^2)= Square root of (9+1) Which is square root of 10. This is the distance. This works because if we draw a triangle with one side having length 3 and another side having length 1, we have a right triangle. THis is because the side of length 3 is vertical and the side of length 1 is horizontal. Now the hypotenuse of this triangle is the line between the two points in question. So the length of the hypotenuse is the distance between the points. However, the pythagorean theorem tells us this distance is the square root of 1^2 +3^2=Square root of 10
What is the distance between the points 4 7 and 7 8?
The Pythagorean distance is sqrt[(4 - 7)2 + (7 - 8)2] = sqrt[9 + 1] = sqrt(10) = 3.162 approx.
What is the distance between the points 4 5 and 10 13 on a coordinate plane?
The distance along a straight line is 10. Using the Pythagorean equation, c2 = a2 + b2 where the x change is 6 and the y change is 8, c2 = 62 + 82 = 36 + 64 = 100 c = [sqrt 100] = 10
Find the distance between these points A32 B910?
If the points are (3, 2) and (9, 10) then the distance works out as 10
Find the distance between the points-2 -10 and -8 -2?
10
Find the distance between the points -2 -10 and 10 6?
The sq.root of 122+162=20
Find the distance between the points A 9 3 and B 15 11?
10
What is the distance between the points (45) and (1013) on a coordinate plane?
If you mean points of (4, 5) and (10, 13) then the distance works out as 10
What is the distance between the points (22) and (8-6)?
Points: (2, 2) and (8, -6) Distance: 10
What is the distance between the points (10 12) and (4 36)?
The distance between points can be calculated using Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((4 - 10)² + (36 - 12)²) → distance = √((-6)² + (24)²) → distance = √(36 + 576) → distance = √612 → distance = 6 √17 ≈ 24.74 units.
What is the distance between the points -6-10 and 25?
If you mean points of: (-6, -10) and (2, 5) then it works out as 17
What is the distance between the points (4 5) and (10 13) on a coordinate plane?
10 units
Find the distance between the two points -10 8 and -2 -7?
(-10--2)2+(8--7)2 = 289 and the square root of this is 17 Therefore the distance is 17 units in length.
Find the distance between points -6 1 and 10 -8?
If d is the distance between them, then d2 = (-6 -10)2 + (1 - (-8))2 = (-16)2 + 92 =256 + 81 = 337 so d = sqrt(337) = 18.36
What is the distance between the points (45) and (103) on a coordinate plane?
The distance between (4, 5) and (10, 3) = sqrt(40) = 2*sqrt(10) = 6.3246 approx.
