x + 7y = 33 multiply through by 3: 3x + 21y = 99
Subtract the second equation from the above equation: 23y = 92
So y = 4
Substituting this value of y in the first equation,
x + 28 = 33 ie x = 5
The solution is (x,y) = (5,4)
3x + 2y = 7
(2, -1)
3x-2y-7=0
3x+2y = 1 2y = -3x+1 y = -1.5x+0.5
3x+2y=6 2y=-3x+6 y=-1.5x+3
-3x + 2y = 9 2y = 3x + 9y = 1,5x + 4,5
3x + 2y = 7
The ordered pair is (5, 4).
(2, -1)
3x-2y-7=0
3x = 2y + 7 The standard form is: 3x - 2y - 7 = 0
3x+2y = 1 2y = -3x+1 y = -1.5x+0.5
3x+2y=6 2y=-3x+6 y=-1.5x+3
3x+2y=9 2y=9-3x y=-1.5x-4.5
x = 5 and y = 4
3x+2y-5=0 3x+2y=5 Im lost im only 12 work out the rest hope i helped
3x + 2y = 8 This is an equation. It could be the equation of a line.