x + 7y = 33 multiply through by 3: 3x + 21y = 99
Subtract the second equation from the above equation: 23y = 92
So y = 4
Substituting this value of y in the first equation,
x + 28 = 33 ie x = 5
The solution is (x,y) = (5,4)
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3x + 2y = 7
(2, -1)
3x-2y-7=0
3x+2y=6 2y=-3x+6 y=-1.5x+3
3x+2y = 1 2y = -3x+1 y = -1.5x+0.5