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x + 7y = 33 multiply through by 3: 3x + 21y = 99

Subtract the second equation from the above equation: 23y = 92

So y = 4

Substituting this value of y in the first equation,

x + 28 = 33 ie x = 5

The solution is (x,y) = (5,4)

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15y ago

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