2x - 5 = 7
First, you would have to add 5 to both sides
then, you would have to divide 2 by both sides.
The answer is 6
Slope for the equation y equals 7 is zero.
It is an equation and the value of g is 2.
7
im assuming your equation is 2x + 1 = 7 in this case you need to find what x equals 2x + 1 = 7 2x + 1 - 1 = 7-1 2x = 6 x = 3 put it back into the equation to check if your answer is correct 2(3) + 1 = 7 6 + 1 = 7 7 = 7 Correct! if your equation is 2x - 1 = 7 x = 4 check it 2(4) - 1 = 7 8 - 1 = 7 7 = 7 Correct! if your equation is 2x1 = 7 x = 7/2 check it 2(7/2)1 = 7 2(7/2) = 7 2 * 7 / 2 = 7 14/2 = 7 7 = 7 Correct! hope i got your equation right. if not you can message me on my message board to get more help.
2
A 2-step equation that equals 13 could be: 2x + 7 = 13. To solve this equation, first subtract 7 from both sides to isolate the variable: 2x = 6. Then, divide both sides by 2 to solve for x: x = 3. Therefore, when x = 3, the equation 2x + 7 equals 13.
13
2+2+2+2+2-7 This is an equation that uses 5 2's yet equals 3.
When you are solving a 2-step equation, you do the opposite of a 1-step equation. You do addition and subtraction first, then the multiplication second. Example: 2x + 9=16 -9 -9 2x=7 Now it's a 1-step equation 2x=7 /2 /2 Your answer would be 3.5 To check all you do is replace the variable with your answer. 2x + 9=16 2(3.5) + 9=16
Slope for the equation y equals 7 is zero.
x=2/7
2n+4=66
It is an equation and the value of g is 2.
7
It is an equation. Taking it step by step: 17 = 3t - 4 17 + 4 = 3t 21 = 3t 7 = t So the value of t is 7.
7
im assuming your equation is 2x + 1 = 7 in this case you need to find what x equals 2x + 1 = 7 2x + 1 - 1 = 7-1 2x = 6 x = 3 put it back into the equation to check if your answer is correct 2(3) + 1 = 7 6 + 1 = 7 7 = 7 Correct! if your equation is 2x - 1 = 7 x = 4 check it 2(4) - 1 = 7 8 - 1 = 7 7 = 7 Correct! if your equation is 2x1 = 7 x = 7/2 check it 2(7/2)1 = 7 2(7/2) = 7 2 * 7 / 2 = 7 14/2 = 7 7 = 7 Correct! hope i got your equation right. if not you can message me on my message board to get more help.