x=-7
x3 + 7x = 8x2x3 + 7x - 8x2 = 0 [subtract 8x2 from both sides]x(x2 + 7 - 8x) = 0 [factor out x]x(x-1)(x-7) = 0 [factor]Since the product of the three factors x, x-1, and x-7 equals zero, any of the three expressions could equal zero:x = 0x - 1 = 0, x = 1x - 7 = 0, x = 7Therefore, there are three solutions to the equation x3 + 7x = 8x2:x = 0x = 1x = 7Or, in set notation: x = {0,1,7}
Double first equation: 10x + 2y = 10Subtract second equation: 7x = 7x = 1, y = 0
7x = -3y + 12
Why not? The statement is trivially true, meaning it holds for all values of x.
7x + 9 = 51 7x = 42 x = 42/7 = 6
x3 + 7x = 8x2x3 + 7x - 8x2 = 0 [subtract 8x2 from both sides]x(x2 + 7 - 8x) = 0 [factor out x]x(x-1)(x-7) = 0 [factor]Since the product of the three factors x, x-1, and x-7 equals zero, any of the three expressions could equal zero:x = 0x - 1 = 0, x = 1x - 7 = 0, x = 7Therefore, there are three solutions to the equation x3 + 7x = 8x2:x = 0x = 1x = 7Or, in set notation: x = {0,1,7}
-2x + 8 = 7x - 10 is technically an equation, in and of itself.
7x - 2 = 60 Add '2' to both sides 7x = 62 Divide both sides by; ;7; # 7x/7 = 62/7 x = 8 6/7 = 857142.....
7x + y = 8 Subtract 7x from each side of the equation: y = -7x + 8
Double first equation: 10x + 2y = 10Subtract second equation: 7x = 7x = 1, y = 0
7x = -3y + 12
-10 + 7x + 4x = 78 Collect like terms -10 + 11x = 78 Add '10' to both sides 11x = 88 Divide both sides by '11' 11x/11 = 88/11 x = 8 The answer!!!!!
Why not? The statement is trivially true, meaning it holds for all values of x.
7x + 9 = 51 7x = 42 x = 42/7 = 6
Im guessing that the equation is 7x - 2y +3z= 19 so the answer is 7x + 3z= 19
It is an equation and the value of x is 2
It is an equation and the value of x is 8