x + 4
If you mean: xsquared+8x-48 then it factors to (x-4)(x+12)
x2 + 2x - 48 = x2 + 8x - 6x - 48 = x(x + 8) - 6(x + 8) = (x - 6)(x + 8)
x2+8x+4 Delta = 82-4x1x4 = 48 = 4 x sqrt(3) so x2+8x+4= (x-((-8-sqrt(48))/2) (x-((-8+sqrt(48))/2) = (x+4+2 sqrt(3)) (x + 4 -2 sqrt(3))
x2-8x=0 ( add 8x to both sides) x2 =8x (divide by x) x=8 ( x2divided by x equals x)
x + 4
If that's + 8x - 48, the answer is (x + 12)(x - 4) If that's - 8x - 48, the answer is (x - 12)(x + 4)
If you mean: xsquared+8x-48 then it factors to (x-4)(x+12)
x² + 8x - 48 = (x + 12)(x - 4) x² + 8x + 48 = (4+(√32)i)(4-(√32)i)
x2 + 2x - 48 = x2 + 8x - 6x - 48 = x(x + 8) - 6(x + 8) = (x - 6)(x + 8)
x2+8x+4 Delta = 82-4x1x4 = 48 = 4 x sqrt(3) so x2+8x+4= (x-((-8-sqrt(48))/2) (x-((-8+sqrt(48))/2) = (x+4+2 sqrt(3)) (x + 4 -2 sqrt(3))
(x2 + 14 + 48 / (x + 8) = (x2 + 62) / (x + 8) =(x2 + 8x - 8x - 64 + 126) / (x + 8) = x - 1 + 126/(x+8)
No, it is a monomial.
X2 + 8x + 16 = 10x +16x2 + 8x + 16=2x + 8x + 16=10x + 16
x2-8x=0 ( add 8x to both sides) x2 =8x (divide by x) x=8 ( x2divided by x equals x)
x^2 - 8z - 48 Factor ( x - 12)(x + 4)
If that's + 8x, the answer is 4(x2 + 2x - 6) If that's - 8x, the answer is 4(x2 - 2x - 6)