x2 + 8x + 15 = (x + 3)(x + 5)
(x + 4)(x +4) or (x + 4)squared
x2 + 8x - 20 = (x - 2)(x + 10).
You ignore the constant part (-3 in this case), calculate half of the coefficient of the linear part (8, in this case), and square this half. (1/2 of 8 is 4; the square of 4 is 16). This gives you the perfect square x2 + 8x + 16. To get something equivalent to the original expression, you must both add and subtract 16, and include the term which I previously ignored (-3): x2 + 8x + 16 - 16 - 3, which you can write as (x2 + 8x + 16) - 16 - 3. The part within parentheses is the perfect square.
x² + 8x + 15 = (x + 5)(x + 3)
x + 4
(x2 - x - 20) / (x2 + 8x + 16) = [(x - 5)(x + 4)] / (x + 4)2 = (x - 5) / (x + 4)
x2+8x+9 = -7 x2+8x+9+7 = 0 x2+8x+16 = 0 (x+4)(x+4) = 0 Therefore: x = -4 and also x = -4 (they both have equal roots)
x*x - 8x +16 = 0 x*x = 8x + 16 x - 16 = _/8x x_/-4 = 2 x = 2
x2 + 8x - 6 = 0 x2 + 8x + 16 = 22 (x + 4)2 = 22 x + 4 = ± √22 x = -4 ± √22
x2 + 8x - 5 = 0 ∴ x2 + 8x + 16 = 21 ∴ (x + 4)2 = 21 ∴ x + 4 = ± √21 ∴ x = -4 ± √21
(x-4)(x-4)
2 this Domo
x2 + 8x + 15 = (x + 3)(x + 5)
x2 + 8x + 15 = (x + 3) (x + 5).
x2 + 8x - 2 = 0 => x2 + 8x = 2 => x2 + 8x + 16 = 2 + 16 = 18 => (x + 4)2 = 18 => x + 4 = +or- sqrt(18) = +or- 3*sqrt(2) so x = -4 +or- 3*sqrt(2)
(x + 4)(x +4) or (x + 4)squared