A common number between 1 and 9999 is 1000. This number is unique because it is the midpoint of the range and represents a significant milestone in counting. Additionally, 1000 is the smallest four-digit number and holds a special place in mathematics as the base unit in the decimal system.
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The sum of all numbers between 1 and n = n*(n+1)/2 The sum of all numbers between 1 and 999 = 999*1000/2 = 499500 The sum of all numbers between 1 and 9999 = 9999*10000/2 = 49995000 So, the sum of all numbers between 1000 and 9999 = 49495500
9999 is the largest 4-digit number.When added with 1 it becomes 10000. 9999 + 1 = 10000.
To be palindromic, the year must be of the form XYYX where X and Y are digits, so we need only consider the first half of the number, namely the XY and the question becomes how many numbers XY are there between 20 and 99 such that XYYX is between 2000 and 9999.The answer depends upon the definition of "between":If "between" means strictly between, that is the year cannot be 2000 or 9999XY = 20 ⇒ 2002 > 2000 so allowed XY = 99 ⇒ 9999 = 9999 so not allowed⇒ number of years is 99 - 20 = 79If "between" means between but also including the limits, that is the year could be 2000 or 9999XY = 20 ⇒ 2002 > 2000 so allowed XY = 99 ⇒ 9999 = 9999 so still allowed⇒ number of years is 99 - 20 + 1 = 80
To express 0.0009999 as a fraction, we first count the number of decimal places, which is four. Next, we write the decimal as the numerator over 10 raised to the power of the number of decimal places, which gives us 9999/10000. Finally, we simplify the fraction by dividing both the numerator and denominator by their greatest common divisor, which in this case is 1, resulting in the simplified fraction 9999/10000.
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