answersLogoWhite

0

its the same as itself. since there is no radical part

User Avatar

Wiki User

∙ 13y ago

What else can I help you with?

Related Questions

What is conjugate of an irrational number?

The conjugate of an irrational number is a non-zero number such that the product of the two numbers is rational. In high school mathematics, you are usually required to know only the conjugates of surds of the form a + b*sqrt(x). The conjugate is a - b*sqrt(x) [-a + b*sqrt(x) is also a conjugate - all you need to do is to switch the sign of one of the two terms.]


How do you rationalise the denominator?

It depends on what the denominator was to start with: a surd or irrational or a complex number. You need to find the conjugate and multiply the numerator by this conjugate as well as the denominator by the conjugate. Since multiplication is by [conjugate over conjugate], which equals 1, the value is not affected. If a and b are rational numbers, then conjugate of sqrt(b) = sqrt(b) conjugate of a + sqrt(b) = a - sqrt(b), and conjugate of a + ib = a - ib where i is the imaginary square root of -1.


What is the graphical relationship between a conjugate number and a complex number?

Graphically, the conjugate of a complex number is its reflection on the real axis.


What is the conjugate of -9?

The conjugate of a real number is simply the number itself, as conjugates typically refer to complex numbers. Since -9 is a real number and does not have an imaginary part, its conjugate is also -9. In summary, the conjugate of -9 is -9.


What is the conjugate of a real number?

Since the imaginary portion of a real number is zero, the complex conjugate of a real number is the same number.


What is the relationship between a complex number and its conjugate?

When a complex number is multiplied by its conjugate, the product is a real number and the imaginary number disappears.


Is the product of any two irrational numbers is an irrational?

No. The product of sqrt(2) and sqrt(2) is 2, a rational number. Consider surds of the form a+sqrt(b) where a and b are rational but sqrt(b) is irrational. The surd has a conjugate pair which is a - sqrt(b). Both these are irrational, but their product is a2 - b, which is rational.


Find the Conjugate of 84-63i?

The conjugate of a complex number is formed by changing the sign of its imaginary part. For the complex number (84 - 63i), the conjugate is (84 + 63i).


What is the importance of the conjugate in rationalizing the denominator of a rational expression that has a radical expression in the denominator?

To eliminate the radical in the denominator.


Is 3.456 a rational or irrational number?

It is a rational number. It can be written as a fraction.


What is the conjugate of -3?

For any number (a + bi), its conjugate is (a - bi), so the real part stays the same, and the imaginary part is negated.For this one, conjugate of [-3 - 9i] is: -3 + 9i


Which polynomial has rational coefficients a leading leading coefficient of 1 and the zeros at 2-3i and 4?

There cannot be such a polynomial. If a polynomial has rational coefficients, then any complex roots must come in conjugate pairs. In this case the conjugate for 2-3i is not a root. Consequently, either (a) the function is not a polynomial, or (b) it does not have rational coefficients, or (c) 2 - 3i is not a root (nor any other complex number), or (d) there are other roots that have not been mentioned. In the last case, the polynomial could have any number of additional (unlisted) roots and is therefore indeterminate.