How about the diagonals of a polygon or a transversal line cutting through parallel lines.
2x+438395 NUT
two ways : 1. calculate the slope of the two lines, if it is same, they are parallel. 2. draw a perpendicular line ( 90 degrees) from on of the lines and if it intersects the other line at 90degrees then they are parallel -HD
The shortest distance between two paralle lines is the length of the line that is perpendicular to both line and intersects both.
pakyuu
A transversal line intersects parallel lines creating various angles.
How about the diagonals of a polygon or a transversal line cutting through parallel lines.
A transverse line.
2x+438395 NUT
two ways : 1. calculate the slope of the two lines, if it is same, they are parallel. 2. draw a perpendicular line ( 90 degrees) from on of the lines and if it intersects the other line at 90degrees then they are parallel -HD
The shortest distance between two paralle lines is the length of the line that is perpendicular to both line and intersects both.
pakyuu
Maximum 12 intersections are there! You can simply use the formula: No. of intersections = n(n-1)/2 [where 'n' is the number of lines] This is derived as each new line can intersect (at most) all the previously drawn lines. There if there is: 1 line => 0 intersections 2 lines => 1 intersection 3 lines => 3 intersections [1 that was there + 2 by the new line can intersect both the previous lines.] 4 lines => 6 intersections [3 that were already there + 3 because the new line can intersect all the 3 lines that were present previously.]
two intersecting lines cross where they are equal to each other. for example, y=x^2 intersects with y=4 at x=2 and x=-2 because when 4=x^2 x will equal (+/-)2
Being 'perpendicular' would require the lines to be at 'right angles' to each other... So, if working in a 2-dimensional setting, the joining of 3 perpendicular lines would not be possible. If working in a 3-dimensional setting, the answer would be 12. Four from the intersection of the 1st and 2nd lines, four from where the 3rd line intersects initially, and four from where the 3rd line leaves the intersection.
28 points. Each added line n intersects (n-1) other lines. 7 + 6 + 5 + 4 + 3 + 2 +1 = 28 The formula is P = n(n-1)/2, which here is 8x7/2 = 28 It is possible to have any number of points between 28 and 1 if multiple lines intersect at the same point.
In plane (Euclidian) geometry there is only one line through two points. On a sphere, every meridian intersects the north and south poles.