28 points. Each added line n intersects (n-1) other lines. 7 + 6 + 5 + 4 + 3 + 2 +1 = 28
The formula is P = n(n-1)/2, which here is 8x7/2 = 28
It is possible to have any number of points between 28 and 1 if multiple lines intersect at the same point.
Zero; parallel lines never intersect.
The greatest number of intersection points that four coplanar lines can have occurs when no two lines are parallel and no three lines intersect at the same point. In this case, the maximum number of intersection points can be calculated using the formula ( \frac{n(n-1)}{2} ), where ( n ) is the number of lines. For four lines, this results in ( \frac{4(4-1)}{2} = 6 ) intersection points.
false
thre lines that intersect in three points
A triangle? Three lines that intersect in three points.
infinety
Parallel lines NEVER touch, so zero.
The greatest number of intersection points with just four lines is 6.
False. If two lines intersect, they do so at exactly one point, provided they are not parallel. In Euclidean geometry, two distinct lines can either intersect at a single point or be parallel and never intersect at all.
Perpendicular lines are lines that always intersect either at just one point, two points or several more.
Depends on the lines. Anywhere from zero to infinitely many. If they are straight lines, then the answer is zero, one or infinity.
Perpendicular lines intersect at one point only.