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If LCM(2, 3, 4, 5, 6) = L, then the required number is l*k + 1 where k is an integer.

Q: What is a number divisible by 2 3 4 5 6 and has a remainder of 1?

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1, any number that you divide by 2 is either divisible by 2 (even) or not divisible by 2, leaving a remainder of 1 (odd).

It is an integer which, when divided by 2, leaves a remainder of 1.

How about 27

No, because it is an odd number, and only even numbers are divisible by 2

When a number can be divided by another number without leaving a remainder, it is called divisible. For example, 10 is divisible by 2 because when we divide 10 by 2, there is no remainder.

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It is not possible, because the number 4 is divisible by 2, and it's remainder is divisible by 2 also, so whatever number works for the "4 with a remainder of 2", will never work for "2 with a remainder of 1.

1, any number that you divide by 2 is either divisible by 2 (even) or not divisible by 2, leaving a remainder of 1 (odd).

If the number has a remainder of 2 or 4 when divided by 6, it is an even number, so it is not prime number. 6n + 2 = 2 (3n + 1), so it is divisible by 2. 6n + 4 = 2 (3n + 2), so it is divisible by 2. If the number has a remainder of 3 when divided by 6, it is divisible by 3, so it is not a prime number. 6n + 3 = 3 (2n + 1), so it is divisible by 3. However, there are two prime numbers that do not have a remainder of 1 or 5 when divided by 6 : 2 and 3

It is an integer which, when divided by 2, leaves a remainder of 1.

How about 27

No, because it is an odd number, and only even numbers are divisible by 2

Not sure what you mean with "work"; an even number is a number that is divisible by 2, that is, if you divide it by 2, you get no remainder. An odd number, if divided by 2, has a remainder of 1.

Yes, 234 is divisible by 9 because on dividing 234 by 9 we get 26 as quotient and 0 as remainder. A number is divisible by another number if: 1- Quotient is a whole number 2- Remainder is zero

No. Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3: 1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1. (121 = 40 x 3 + 1)

"Divisible by" means that you can carry out the division, and that you'll get a whole number. Or, if you use whole number division, that there will be no remainder. For example: 8 divided by 2 = 4, remainder zero. 8 is divisible by 2. On the other hand, 9 divided by 2 = 4, remainder 1 (on a calculator, you get decimals: 4.5). That means that 9 is not divisible by 2.

When a number can be divided by another number without leaving a remainder, it is called divisible. For example, 10 is divisible by 2 because when we divide 10 by 2, there is no remainder.

Let three consecutive integers be n, n+1 and n+2. If n is divisible by 3 then n+1 and n+2 cannot be divisible by 3 as these numbers will respectively leave remainders of 1 and 2. If n is not divisible by 3 then it will leave a remainder of 1 or 2. If n leaves a remainder of 1, then n+1 leaves a remainder of 2 and n+2 is therefore divisible by 3. If n leaves a remainder of 2, then n+1 is divisible by 3 and n+2 is not divisible by 3 as it leaves a remainder of 1.