Q: What is a number n where if the sum of the digits of the number is divisible by n, then the number itself is divisible by n?

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Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.

Yes.

The rule to decide if a number is divisible by 9 is to look at the sum of the digits. If the sum of the digits is divisible by 9, then so is the number.

A number is divisible by 3 if the sum of its digits is a multiple of 3. A number is divisible by 6 if the sum of its digits is a multiple of 3 and it's even. A number is divisible by 9 if the sum of its digits is a multiple of 9.

If sum of digits of a number is divisible by 3 then the number is divisible by 3. Sum of digits = 5+1+8 = 14 and 14 is not divisible by 3. So 518 is not divisible by 3.

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That means the number itself is divisible by three. the sum of the digits in 144, for example, is 9. 144 divided by 3 is 48. The sum of the digits in 21 is 3. 21 divided by 3 is 7.If the number is an even number and the sum of the digits is divisible by 3, the number is also divisible by 6. 144 is even and the sum of the digits is divisible by 3, so 144 is also divisible by 6. 144/6 = 24. And finally, if the sum is divisible by 9, the number itself is also divisible by 9. 27 is an example of this.

This works with 3, and with 9.

That works with 3 and 9.

A number is divisible by 3 if the sum of its digits is divisible by 3.

n = 1, 3 or 9.

If the sum of the digits of a number is divisible by 3, then the number is divisible by 3.

Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.

No, this number is divisible by 3 and hence is not a prime number. You can tell that fast by adding the individual digits. If that sum is itself divisible by 3, as this one is, then the number itself is divisible by 3.

No. The sum of its digits, 5 + 3 + 1, is divisible by 3, which means the number itself is also divisible by 3.

The sum of the digits is 27, which is divisible by 9, so the number itself is divisible by 9. When divided by 9, it equals 20307.

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