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That means the number itself is divisible by three. the sum of the digits in 144, for example, is 9. 144 divided by 3 is 48. The sum of the digits in 21 is 3. 21 divided by 3 is 7.If the number is an even number and the sum of the digits is divisible by 3, the number is also divisible by 6. 144 is even and the sum of the digits is divisible by 3, so 144 is also divisible by 6. 144/6 = 24. And finally, if the sum is divisible by 9, the number itself is also divisible by 9. 27 is an example of this.

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Q: If the sum of the digit is divisible by 3 the number is divisible by?
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What is a 3 digit number divisible by 7 but not 2 the sum of your digits is 4?

I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I


What is the divisibility of 3?

Add the digits of the number together and if the sum is divisible by 3 then the original number is divisible by 3. The test can be applied to the sum and so the summation can be repeated until a single digit remains; if this digit is 3, 6 or 9 then the original number is divisible by 3.


What is the converse inverse and contrapositive If every digit of a number is divisible by 3 then the number is divisible by 3?

Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.


Is 5673 divisible by 3 or 9?

It is divisible by 3 but not divisible by 9. To test for divisibility by 3, sum the digits and if the sum is divisible by 3 then so is the original number; the test can be repeated ion the sum, so keep summing until a single digit remains and if this single digit is 3, 6 or 9, then the original number is divisible by 3: 5673 → 5 + 6 + 7 + 3 = 21 → 2 + 1 = 3 which is one of {3, 6, 9} so 5673 is divisible by 3. To test for divisibility by 9, sum the digits and if the sum is divisible by 9 then so is the original number; the test can be repeated ion the sum, so keep summing until a single digit remains(this single digit is known as the digital root of the number) and if this single digit is 9, then the original number is divisible by 9: 5673 → 5 + 6 + 7 + 3 = 21 → 2 + 1 = 3 which is not 9 so 5673 is not divisible by 9.


Is 552 divisible by 6?

yes 552 is divisible by 6 and the result is 92... to find out if a number is divisible by 6 then that number must be divisible by 2 and 3.. 1.If a number is divisble by three then the last digit must be divisible by 2 (so that the last digit must be 0,2,4,6,8) in this number the last digit is 2 so that it is divisible by 2 2.If a number is divisble by 3 then the sum of its digit must be divisible by 3. In this case the sum of the digits of 552 is 5+5+2= 12 and 12 is divisible by 3.... If this two rules fit in then that number is divisible by 6

Related questions

What is a 3 digit number divisible by 7 but not 2 the sum of your digits is 4?

I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I


What is the number n where if the sum of the digits of the number is divisible by n the number itself is divisible by n?

3 and 9. 93 has a digit sum of 12, initially, which is divisible by 3, but not by 9. So 93 is divisible by 3, but not by 9. 99 has a digit sum of 18, initially, which is divisible by 3 and 9. So 99 is divisible by both 3 and 9.


What is the divisibility of 3?

Add the digits of the number together and if the sum is divisible by 3 then the original number is divisible by 3. The test can be applied to the sum and so the summation can be repeated until a single digit remains; if this digit is 3, 6 or 9 then the original number is divisible by 3.


What is the converse inverse and contrapositive If every digit of a number is divisible by 3 then the number is divisible by 3?

Converse:If a number is divisible by 3, then every number of a digit is divisible by three. Inverse: If every digit of a number is not divisible by 3 then the number is not divisible by 3? Contrapositive:If a number is not divisible by 3, then every number of a digit is not divisible by three.


What is a 3 digit number divisible by 7 but not 2 the sum of your digits is 4 what number am i?

301


Is the number 26 divisible by 2 3 5 or 9 How do you know?

To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 26 is 6 which is one of {2, 4, 6, 8, 0} so 26 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 26: 2 + 6 = 8 which is not one of {3, 6, 9} so 26 is not divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 26 is a 6 which is not 0 nor 5, so 26 is not divisible by 5. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 26: 2 + 6 = 8 which is not 9 so 26 is not divisible by 9. 26 is divisible by 2 but not divisible by 3, 5 nor 9.


What is a 3 digit number the sum is 4 im divisible by 7 but not by 2?

721


What number between 120 and 130 is divisible by 3 and has a digit sum divisible by 4?

129.129.129.129.


Is 5673 divisible by 3 or 9?

It is divisible by 3 but not divisible by 9. To test for divisibility by 3, sum the digits and if the sum is divisible by 3 then so is the original number; the test can be repeated ion the sum, so keep summing until a single digit remains and if this single digit is 3, 6 or 9, then the original number is divisible by 3: 5673 → 5 + 6 + 7 + 3 = 21 → 2 + 1 = 3 which is one of {3, 6, 9} so 5673 is divisible by 3. To test for divisibility by 9, sum the digits and if the sum is divisible by 9 then so is the original number; the test can be repeated ion the sum, so keep summing until a single digit remains(this single digit is known as the digital root of the number) and if this single digit is 9, then the original number is divisible by 9: 5673 → 5 + 6 + 7 + 3 = 21 → 2 + 1 = 3 which is not 9 so 5673 is not divisible by 9.


Is 552 divisible by 6?

yes 552 is divisible by 6 and the result is 92... to find out if a number is divisible by 6 then that number must be divisible by 2 and 3.. 1.If a number is divisble by three then the last digit must be divisible by 2 (so that the last digit must be 0,2,4,6,8) in this number the last digit is 2 so that it is divisible by 2 2.If a number is divisble by 3 then the sum of its digit must be divisible by 3. In this case the sum of the digits of 552 is 5+5+2= 12 and 12 is divisible by 3.... If this two rules fit in then that number is divisible by 6


Is the number 432 divisible by 2 3 5 6 9 10?

To be divisible by 2 the number must be even, that is its last digit must be 2, 4, 6, 8, or 0; the last digit of 432 is 2 which is one of {2, 4, 6, 8, 0} so 432 is even and divisible by 2. To be divisible by 3 sum the digits of the number; if this sum is divisible by 3 then the original number is divisible by 3. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 3, 6, or 9 then the original number is divisible by 3; For 432: 4 + 3 + 2 = 9 which is one of {3, 6, 9} so 432 is divisible by 3. To be divisible by 5 the last digit must be a 0 or 5; the last digit of 432 is a 2 which is not 0 nor 5, so 432 is not divisible by 5. To be divisible by 6, the number must be divisible by both 2 and 3; these have been tested above and found to be true, so 432 is divisible by 6. To be divisible by 9 sum the digits of the number; if this sum is divisible by 9 then the original number is divisible by 9. The test can be repeated on the sum until a single digit remains, in which case if this single digit is 9 then the original number is divisible by 9; For 432: 4 + 3 + 2 = 9 which is 9 so 432 is divisible by 9 To be divisible by 10 the last digit must be a 0; the last digit of 432 is a 2 which is not 0, so 432 is not divisible by 10. 432 is divisible by 2, 3, 6 and 9, but not divisible by 5 nor 10.


A number is divisible by 3 if the blank is divisible by 3?

A number is divisible by 3 if the sum of its digits is divisible by 3.

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