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If it is assumed that, by saying "divisor" only positive divisors are involved; it may be, "any Prime number" to the power of four. To find the number of the positive divisors of a definite number, we can follow these steps;

1- First, the number should be written in the form: A= ax.by.cz... where; a, b & c are prime numbers. For instance, 12 can be written as: 12=22.31

2- Number of positive divisors are; (x+1).(y+1).(z+1), an equation, which can be found by solving the related probability problem about the possible different combinations of multiplications to form the related number. So, 12 has; (2+1).(1+1)=6 divisors including 1 and itself, which are; 12, 6, 4, 3, 2, 1.

Returning to real problem, since the desired number of positive divisors are 5, equation 2 can only be written as; (4+1).(0+1)=5 So, x=4 & y=0, z=0...

So, the number is; A= a4 i.e; 16, 81, 625 etc...

Q: What is a number that has 5 divisors including 1 and itself?

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positive divisors of 600 inclusive of 1 and 600 itself

Because five is a prime number its only divisors are 1 and itself.

The only numbers which divide into 89 exactly are 1 and 89. These are called factors or divisors. Any number which has exactly 2 divisors (1 and the number itself) is a prime number.

Abundant, deficient and perfect numbers are determined by the sum of the proper divisors (or factors) of a number, which excludes the number itself. The factors of 76 are : 1,2,4,19,38,76 . . . after excluding the number itself the sum of the proper divisors is :- 1+2+4+19+38= 64 Deficient numbers occur when the sum of the proper divisors is less than the number itself. As 64 is less that 76 then it is deficient.

There are no numbers that fit your description.

Related questions

positive divisors of 600 inclusive of 1 and 600 itself

Since 11 is a prime number, its only divisors are 1 and itself.

Because five is a prime number its only divisors are 1 and itself.

No they do not, take a big prime number and compare it to a smaller composite number. The number 6833 as only two factors (divisors), namely 1 and itself. But the number 68 which is much smaller has more factors or divisors. 68 has 2 and 4 and 17 and 1 and itself which is already more divisors than 6833.

47 is prime. Its only factors are 1 and itself.

yes. The only divisors of a prime number are itself and 1. Without counting the prime number, the sum of it's divisors is always 1.

The only numbers which divide into 89 exactly are 1 and 89. These are called factors or divisors. Any number which has exactly 2 divisors (1 and the number itself) is a prime number.

A perfect number is a number that is the sum of its divisors (the divisors exclude the number itself).When the sum of the divisors is greater than a number then that number is abundant.As the number itself is excluded from the divisors then the only divisor of 31 is 1.So, 31 is a deficient number.Note : The first few abundant numbers are 12,18,20,24,30 ... and these continue to be even. The first abundant odd number is 945 = 33 x 5 x 7 for which its divisors total 975.

71 is a prime number so its only divisors are 1 and itself.

Abundant, deficient and perfect numbers are determined by the sum of the proper divisors (or factors) of a number, which excludes the number itself. The factors of 76 are : 1,2,4,19,38,76 . . . after excluding the number itself the sum of the proper divisors is :- 1+2+4+19+38= 64 Deficient numbers occur when the sum of the proper divisors is less than the number itself. As 64 is less that 76 then it is deficient.

Yes. Every number is divisible by itself or 1.

There are no numbers that fit your description.