240 is three digits, and has a '2' in the hundreds column.
240/3 = 80
240/4 = 60
240/5 = 48
2,4,6,8,and 0 are divisible by 2 in the ones digit. Zero is only divisible in a number with 2 digits or more. 0 itself is not divisible by 2.
No, a number with a 9 in the ones place is not always divisible by 3. For a number to be divisible by 3, the sum of its digits must be divisible by 3, regardless of the digit in the ones place. For example, the number 29 has a 9 in the ones place, but its digit sum (2 + 9 = 11) is not divisible by 3.
In the number 63480297, the digit in the millions place is 6, and the digit in the hundreds place is 2. To find the sum of these digits, you add them together: 6 + 2 = 8. Therefore, the sum of the digits in the millions and hundreds place values is 8.
The digit in the hundreds place of the number 1098 is 0. In the number 1098, the digits are arranged as follows: 1 in the thousands place, 0 in the hundreds place, 9 in the tens place, and 8 in the ones place.
In the number 6397, the digit in the hundreds place is 6. The place values of the digits from right to left are units (7), tens (9), hundreds (3), and thousands (6). Therefore, the hundreds place represents the value of 600.
If the number formed by the last three digits is divisible by 8. This requires that: if the digit in the hundreds place is even, the last two digits must form a number divisible by 8 and if the digit in the hundreds place is odd, the last two digits must form a number divisible by 4 but not by 8.
2,4,6,8,and 0 are divisible by 2 in the ones digit. Zero is only divisible in a number with 2 digits or more. 0 itself is not divisible by 2.
Sol. Since the given number is divisible by 5, so 0 or 5 must come in place of $. But, a number ending with 5 is never divisible by 8. So, 0 will replace $. Now, the number formed by the last three digits is 4*0, which becomes divisible by 8, if * is replaced by 4. Hence, digits in place of * and $ are 4 and 0 respectively.
To know if a number is composite without listing its factors, you can use these rules:All numbers that end with 2, 4, 6, 8, and 0 (even numbers) are divisible by 2.If the sum of the digits in a number is divisible by 3, the number is divisible by 3.If the last two digits are divisible by 4, the number is divisible by 4.All numbers that have 5 in the one's place are divisible by 5.If a number is divisible by 2 AND is divisible by 3, it is divisible by 6.If the last 3 digits of a number are divisible by 8, the number is divisible by 8.If the sum of the digits of number is divisible by 9, the number is divisible by 9.If a number ends wuth 0, the number is divisible by 10.
In the number 63480297, the digit in the millions place is 6, and the digit in the hundreds place is 2. To find the sum of these digits, you add them together: 6 + 2 = 8. Therefore, the sum of the digits in the millions and hundreds place values is 8.
No, a number with a 9 in the ones place is not always divisible by 3. For a number to be divisible by 3, the sum of its digits must be divisible by 3, regardless of the digit in the ones place. For example, the number 29 has a 9 in the ones place, but its digit sum (2 + 9 = 11) is not divisible by 3.
240
The one that has a 3, 6 or 9 there.
It is: 3 which represents 300
The digit in the hundreds place of the number 1098 is 0. In the number 1098, the digits are arranged as follows: 1 in the thousands place, 0 in the hundreds place, 9 in the tens place, and 8 in the ones place.
In the number 6397, the digit in the hundreds place is 6. The place values of the digits from right to left are units (7), tens (9), hundreds (3), and thousands (6). Therefore, the hundreds place represents the value of 600.
A 3-digit odd number that has 3 in the hundreds place and is divisible by 7 is 357. This number meets all the criteria: it is a 3-digit number, odd, has 3 in the hundreds place, and when divided by 7, it results in 51, confirming its divisibility.