240 is three digits, and has a '2' in the hundreds column.
240/3 = 80
240/4 = 60
240/5 = 48
2,4,6,8,and 0 are divisible by 2 in the ones digit. Zero is only divisible in a number with 2 digits or more. 0 itself is not divisible by 2.
To find a number with 8 in the hundreds place, think about what the hundreds place means. In a number like 832, the hundreds place is the third digit from the right. So, if a number has 8 in the hundreds place, it looks like 8 _ _, where the _ _ can be any digits. For example, 832 has 8 in the hundreds place. Another example is 854, or 879. In each of these numbers, 8 is in the hundreds place. So, any number between 800 and 899 has an 8 in the hundreds place.
240
It is assumed that the question requires each of the four digits to be used once and only once - ie permutations of {1, 2, 3, 4}. Since 100 is divisible by 4, any number of hundreds is divisible by 4. So the test of divisibility by 4 reduces to whether the last two digits are divisible by 4. For each pair of digits in the tens and units place that satisfy this requirement, the first two (thousands and hundreds) can be selected in two ways. So there are two numbers ending in 12 two ending in 24 and two ending in 32 six in all.
Are you asking what the divisibility rule for 4 is?===========A number is divisible by 5 if it ends in a 0 or a 5=====There are two ways to test for divisibility by 4.A number is divisible by 4 if it is divisible by 2 twice. That is, the factor you get when you factor a 2 out must also be divisible by 2.Example... is 516 divisible by 4?Well, is it divisible by 2? Yes, it is even. Factor that 2 out you get 258. Is 258 also divisible by 2? Yes, it too is even. Since it was divisible by 2 and the quotient was also divisible by 2 then the original was divisible by 4.But, 4's have another rule that is simpler.All you have to do is look at the smallest two digits: the ones and tens place. You can ignore anything in the hundreds place or up. If the ones and tens place form a number that is divisible by 4 then the whole number is also divisible by 4Example: Is 52848474116 divisible by 4?Just take the last two digits off and test them. 16. Is 16 divisible by 4? Yes, so that whole mess of a number is also.
If the number formed by the last three digits is divisible by 8. This requires that: if the digit in the hundreds place is even, the last two digits must form a number divisible by 8 and if the digit in the hundreds place is odd, the last two digits must form a number divisible by 4 but not by 8.
2,4,6,8,and 0 are divisible by 2 in the ones digit. Zero is only divisible in a number with 2 digits or more. 0 itself is not divisible by 2.
Sol. Since the given number is divisible by 5, so 0 or 5 must come in place of $. But, a number ending with 5 is never divisible by 8. So, 0 will replace $. Now, the number formed by the last three digits is 4*0, which becomes divisible by 8, if * is replaced by 4. Hence, digits in place of * and $ are 4 and 0 respectively.
To know if a number is composite without listing its factors, you can use these rules:All numbers that end with 2, 4, 6, 8, and 0 (even numbers) are divisible by 2.If the sum of the digits in a number is divisible by 3, the number is divisible by 3.If the last two digits are divisible by 4, the number is divisible by 4.All numbers that have 5 in the one's place are divisible by 5.If a number is divisible by 2 AND is divisible by 3, it is divisible by 6.If the last 3 digits of a number are divisible by 8, the number is divisible by 8.If the sum of the digits of number is divisible by 9, the number is divisible by 9.If a number ends wuth 0, the number is divisible by 10.
240
The one that has a 3, 6 or 9 there.
It is: 3 which represents 300
415
315
There are ten. The lowest is 1100 and the others are that plus all the multiples of 11 up to 1199...
To find a number with 8 in the hundreds place, think about what the hundreds place means. In a number like 832, the hundreds place is the third digit from the right. So, if a number has 8 in the hundreds place, it looks like 8 _ _, where the _ _ can be any digits. For example, 832 has 8 in the hundreds place. Another example is 854, or 879. In each of these numbers, 8 is in the hundreds place. So, any number between 800 and 899 has an 8 in the hundreds place.
Yes, 268 is divisible by 2 and 4. To check if a number is divisible by 2, we just need to look at the ones place digit. If it is even, then the number is divisible by 2. In this case, the ones place digit of 268 is 8, which is even, so 268 is divisible by 2. To check if a number is divisible by 4, we need to look at the last two digits of the number. If the last two digits