Every number is divisible by any non-zero number. 527 is not evenly divisible by 3.
Every number is divisible by any non-zero number. Furthermore, 5835 is evenly divisible by 3.
yeah3 9 15 21 27 and so on(every other multiple of three)But if you have a large number, like 755253, and don't have a calculator handy, then use sum of digits to determine if divisible by 3.Then if the number is divisible by 3 and divisible by 2, then it is also divisible by 6.So in this case: 7 + 5 + 5 + 2 + 5 + 3 = 27, which is divisible by 3, but the original number is odd, so the number is not divisible by 6.
If a number is divisible by both three and four, it's divisible by twelve.
To determine if a number is divisible by 3, you need to add up its individual digits. In this case, 7 + 9 + 6 + 0 = 22. Since 22 is not divisible by 3 (it does not result in a whole number), 7960 is not divisible by 3.
240
315
240
The digit in the hundreds place in the number 2378.91 is the digit 3.
240 is three digits, and has a '2' in the hundreds column. 240/3 = 80 240/4 = 60 240/5 = 48
261, 264, or 267
There are 3 hundreds in the number 398. This can be determined by looking at the digit in the hundreds place, which is 3. This digit represents the number of hundreds in the overall number.
hundreds
A number is divisible by 12 if it is divisible by 3 AND it is divisible by 4. Rule 1a (Divisibility by 3): Add up all the digits of the number. Is this number divisible by 3? Rule 1b (Divisibility by 4): Is the number formed by the last two digits of the original number (the number left after deleting the hundreds, thousands, millions etc) divisible by 4? If the answer to 1a is NO, then the number is not divisible by 3 and so not divisible by 12. In this case, obviously, rule 1b is irrelevant. If the answer to 1b is NO, then the number is not divisible by 4 and so not divisible by 12. If the answer to both 1a and 1b is YES, then the number is divisible by 12.
There is no unique answer - there are seven such numbers. More information in required to narrow down the field.
102 is divisible by: 1 2 3 6 17 34 51 102.
3