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What is the expression of The product of a number and 2 is 3 less than the quotient of a number and 2.?
2m = n/2 - 3 where m and n are the two numbers.
What 2 numbers with a sum of 12 and a product of 35?
Let the numbers by 'm' & 'n' Hence m + n = 12 mn = 35 Hence m = 35/n Substitute 35/n + n = 12 Multiply through by 'n' 35 + n^2 = 12n n^2 - 12n + 35 = 0 It is now in Quadratic Form ; Factor ( n - 7)(n - 5) = 0 Hence n= 7 or n= 5 It follows that m = 5 , or m = 7
What are your two numbers if their sum is -5 and their product is 4?
Let the number be 'm' & 'n' Hence Sum = m + n = -5 Product = mn = 4 Algebraically rearrange the product to m = 4/n Substitute into the Sum (4/n) + n = -5 Multiply through by 'n' Hence 4 + n^2 = -5n n^2 + 5n + 4 = 0 It is not in Quadrtatic form . to solve. Hence (n - 1)(n - 4) = 0 n = -1 & n = -4 Are the two numbers.
Product of 5m plus half of n?
5(m+/n
When a trinomial is factored as (x m)(x n) what is the product of m and n?
It is the constant term of the trinomial.
What is the product of 5 and m plus half of n?
If we are to find the product of 5 and m and n/2 (which is half of n), we have: 5 times m times n/2 = 5 x m x n/2 = 5mn/2
Where m and n are statements m n is called the of m and n?
Where m and n are statements m n is called the _____ of m and n.
If m and n are prime numbers such that the sum of m and n is greater than 20 and the product of m and n is less than 50 What is a possible value of the product of m and n?
38 or 46
What is the expression of The product of a number and 2 is 3 less than the quotient of a number and 2.?
2m = n/2 - 3 where m and n are the two numbers.
Two numbers have a sum of -9 and a product of -90 What are the numbers?
Let the two numbers be 'm' & 'n' Sum = m + n = -9 Product is mn = -90 Hence m = -90/n Substitute -90/n + n = -9 Multiply through by 'n' -90 + n^2 = - 9n n^2 + 9n - 90 = 0 It is now in quadratic form ; factor (n + 15)(n - 6) = 0 n = -15 & n = 6
What 2 numbers with a sum of 12 and a product of 35?
Let the numbers by 'm' & 'n' Hence m + n = 12 mn = 35 Hence m = 35/n Substitute 35/n + n = 12 Multiply through by 'n' 35 + n^2 = 12n n^2 - 12n + 35 = 0 It is now in Quadratic Form ; Factor ( n - 7)(n - 5) = 0 Hence n= 7 or n= 5 It follows that m = 5 , or m = 7
What is the magnitude of cartesian product?
The Cartesian product of two sets, A and B, where A has m distinct elements and B has n, is the set of m*n ordered pairs. The magnitude is, therefore m*n.
What is the product of 8 and the sum of 6?
mn = 8 ( Product) m + n = 6 (Sum) Hence m = 6 - n Substitute (6 -n)n = 8 Multiply out the brackets 6n - n^(2) = 8 n^(2) - 6n + 8 = 0 It is now in quadratic form and will factor Hence ((n - 2)(n - 4) = 0 n = 2 & n = 4 So '2' & '4' are the two numbers. Verification 2 + 4 = 6 2 x 4 = 8
What are your two numbers if their sum is -5 and their product is 4?
Let the number be 'm' & 'n' Hence Sum = m + n = -5 Product = mn = 4 Algebraically rearrange the product to m = 4/n Substitute into the Sum (4/n) + n = -5 Multiply through by 'n' Hence 4 + n^2 = -5n n^2 + 5n + 4 = 0 It is not in Quadrtatic form . to solve. Hence (n - 1)(n - 4) = 0 n = -1 & n = -4 Are the two numbers.
M plus the product of 6 and n?
m+6n
If the product is 80 and the sum us 21 what are the numbers?
Let the number be 'm' & 'n' Hence Product ; mn = 80 Sum ; m + n = 21 m = 21 - n Substitute (21 - n) n = 80 21n - n^2 = 80 n^2 - 21 n + 80 = 0 It is now in quadratic form to factor. ( n - 16)(n - 5) = 0 Hence the numbers are 5 & 16
Product of 5m plus half of n?
5(m+/n
