A 4 sided arrowhead quadrilateral would fit the description.
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In a regular polygon with ( n ) sides, the number of non-intersecting diagonals that can be drawn is given by the formula ( \frac{n(n-3)}{2} ). However, if you are looking for the number of ways to draw non-intersecting diagonals that divide the polygon into triangles (triangulation), the count is represented by the ( (n-2) )-th Catalan number, which is ( C_{n-2} = \frac{1}{n-1} \binom{2(n-2)}{n-2} ). Thus, the interpretation of "non-intersecting diagonals" can vary based on context.
Yes, any quadrilateral has diagonals.
If the diagonals of a quadrilateral are perpendicular to each other, then the quadrilateral is a square.Or a kite.
A quadrilateral has 2 diagonals. It does not matter whether it is convex or not.
A quadrilateral has two and only two diagonals. That's the maximum and also the minimum. If it has more or fewer than two diagonals, it's not a quadrilateral.