|p| = 2.
P2 + 13p - 30 = 0 Answer: p= -15, p = 2
It depends on what aspect of constant velocity you are talking about. Since the velocity is not changing, one valid equation is: V = [number] At the same time, acceleration is zero, so another equation is: A = 0 If "p" is position and p1 is the original position and p2 is the current position after tine lapse "t," then: p2 = p1 + Vt
p2 + 2pq + q2 = 1q2 + 2pq + (p2 - 1) = 0q = 1/2 [ -2p plus or minus sqrt( 4p2 - 4p2 + 4 ) ]q = -1 - pq = 1 - p
You use the well-known point-point formula . Here is it: suppose P1 = (x1,y1) and P2 = (x2,y2) An equation for the line containing P1 and P2 is y - y1 = [(y1-y2)/(x1-x2)] (x -x1) Note that the quantity in brackets is the slope of the line. Note also that it does not matter which point is P1 and which is P2.
An equation that is always true is an identity.
The frequency of the homozygous dominant genotype.
To solve Boyle's Law equation for V2, first write the equation as P1V1 = P2V2. Then rearrange it to isolate V2 on one side, dividing both sides by P2 to solve for V2, which will be V2 = (P1 * V1) / P2.
P2 + 13p - 30 = 0 Answer: p= -15, p = 2
It depends on what aspect of constant velocity you are talking about. Since the velocity is not changing, one valid equation is: V = [number] At the same time, acceleration is zero, so another equation is: A = 0 If "p" is position and p1 is the original position and p2 is the current position after tine lapse "t," then: p2 = p1 + Vt
p2 + 2pq + q2 = 1q2 + 2pq + (p2 - 1) = 0q = 1/2 [ -2p plus or minus sqrt( 4p2 - 4p2 + 4 ) ]q = -1 - pq = 1 - p
You use the well-known point-point formula . Here is it: suppose P1 = (x1,y1) and P2 = (x2,y2) An equation for the line containing P1 and P2 is y - y1 = [(y1-y2)/(x1-x2)] (x -x1) Note that the quantity in brackets is the slope of the line. Note also that it does not matter which point is P1 and which is P2.
According to Boyle's law, P1V1 = P2V2. P1 = 74atm V1 = 190mL P2 = ? V2 = 30.0mL Solve for P2. 74atm x 190mL = P2 x 30.0mL 74atm x 190mL/30.0mL = P2 470atm = P2 (469 rounded to two significant figures due to 190mL and 74atm.)
If you have p1, p2, p3, and p4, it seems like you are referring to four different entities, possibly variables or parameters in a system or mathematical equation. Without further context, it is difficult to provide a specific interpretation or action related to p1, p2, p3, and p4.
(p1/v1) = (p2/v2)For Apex (P1 N1)= (P2N2 )
It is not an equation, but q2 meaning q^2 represents q being multiplied by itself.
Any number that makes an equation true is a 'solution of an equation'. it is a solution
Pascal's law states that a change in pressure applied to an enclosed fluid is transmitted undiminished to all portions of the fluid and to the walls of its container. The equation for Pascal's law is P1 = P2, where P1 is the initial pressure applied to the fluid and P2 is the final pressure exerted throughout the fluid.