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Find the value or values of p in the quadratic equation p2 plus 13p - 30 equals 0?
P2 + 13p - 30 = 0 Answer: p= -15, p = 2
What is q in this equation p2 plus 2pq plus q2 equals 1?
p2 + 2pq + q2 = 1q2 + 2pq + (p2 - 1) = 0q = 1/2 [ -2p plus or minus sqrt( 4p2 - 4p2 + 4 ) ]q = -1 - pq = 1 - p
Equation for constant volocity?
It depends on what aspect of constant velocity you are talking about. Since the velocity is not changing, one valid equation is: V = [number] At the same time, acceleration is zero, so another equation is: A = 0 If "p" is position and p1 is the original position and p2 is the current position after tine lapse "t," then: p2 = p1 + Vt
How do you find the equation of a line when given two different points?
You use the well-known point-point formula . Here is it: suppose P1 = (x1,y1) and P2 = (x2,y2) An equation for the line containing P1 and P2 is y - y1 = [(y1-y2)/(x1-x2)] (x -x1) Note that the quantity in brackets is the slope of the line. Note also that it does not matter which point is P1 and which is P2.
How to determine if points lie on a straight line?
Take any two points and form the equation for a straight line. If all the remaining points satisfy the equation, then they lie on astraight line. Else, they don't. Here's an example. Consider n points as P1(x1, y1), P2(x2, y2), ...., Pn(xn, yn). In order to determine if P1, P2, ..., Pn lie on a straight line, form the straight line equation with P1 and P2 as: y-y1= m * (x - x1), where the slope m = (y2-y1)/(x2-x1). Then try to satisfy this equation by the remaining points P3, P4, ..., Pn. That is, verify the following: Is y3-y1= m * (x3 - x1)? Is y4-y1= m * (x4 - x1)? ... Is yn-y1= m * (xn - x1)? If all of the above is true, then the points lie on a straight line.
What does the Hardy Weinberg equation p2 represent?
The frequency of the homozygous dominant genotype.
How do you solve boyles law equation for V2?
To solve Boyle's Law equation for V2, first write the equation as P1V1 = P2V2. Then rearrange it to isolate V2 on one side, dividing both sides by P2 to solve for V2, which will be V2 = (P1 * V1) / P2.
Find the value or values of p in the quadratic equation p2 plus 13p - 30 equals 0?
P2 + 13p - 30 = 0 Answer: p= -15, p = 2
What is q in this equation p2 plus 2pq plus q2 equals 1?
p2 + 2pq + q2 = 1q2 + 2pq + (p2 - 1) = 0q = 1/2 [ -2p plus or minus sqrt( 4p2 - 4p2 + 4 ) ]q = -1 - pq = 1 - p
Equation for constant volocity?
It depends on what aspect of constant velocity you are talking about. Since the velocity is not changing, one valid equation is: V = [number] At the same time, acceleration is zero, so another equation is: A = 0 If "p" is position and p1 is the original position and p2 is the current position after tine lapse "t," then: p2 = p1 + Vt
How do you find the equation of a line when given two different points?
You use the well-known point-point formula . Here is it: suppose P1 = (x1,y1) and P2 = (x2,y2) An equation for the line containing P1 and P2 is y - y1 = [(y1-y2)/(x1-x2)] (x -x1) Note that the quantity in brackets is the slope of the line. Note also that it does not matter which point is P1 and which is P2.
A gas of 190mL at a pressure of 74 atm can be expected to change its pressure when its vloume changes to 30.0 mL express its nes pressure in units of atmospheres?
Using the combined gas law equation (P1V1 = P2V2), we can find the new pressure. Rearranging the equation to solve for P2 gives us P2 = (P1V1) / V2. Plugging in the values gives P2 = (74 atm * 190 mL) / 30.0 mL = 470 atm. Therefore, the gas's new pressure is 470 atm.
What if you have p1 p2 p3 and p4?
If you have p1, p2, p3, and p4, it seems like you are referring to four different entities, possibly variables or parameters in a system or mathematical equation. Without further context, it is difficult to provide a specific interpretation or action related to p1, p2, p3, and p4.
Which of the following is not a valid equation for describing the behavior for gases?
(p1/v1) = (p2/v2)For Apex (P1 N1)= (P2N2 )
If a gas has a pressure of 50.0 mm Hg at 540 K what will be the pressure at 200K if the volume does not change?
If you dcrease the temperature you will decrease the pressure proportionately. So, T1 over T2 will equal P1 over P2. We can derive the formula P1 x T2 = P2 x T1. Substitue the values and we get 50.0 mm x 200K = P2 x 540K 10,000 mmK = P2 x 540K 10,000mmK / 540K = P2 P2 = 18.52 mm of Mercury in a constant volume
What does q2 represent in the equation p2 plus 2pq plus q2 plus 1?
It is not an equation, but q2 meaning q^2 represents q being multiplied by itself.
Pascal's law equation?
Pascal's law states that a change in pressure applied to an enclosed fluid is transmitted undiminished to all portions of the fluid and to the walls of its container. The equation for Pascal's law is P1 = P2, where P1 is the initial pressure applied to the fluid and P2 is the final pressure exerted throughout the fluid.
