A two-digit number that, when divided by 4, leaves a remainder of 1 can be expressed in the form ( n = 4k + 1 ), where ( k ) is an integer. For example, if we take ( k = 2 ), we get ( n = 4(2) + 1 = 9 ), which is not a two-digit number. However, if we take ( k = 3 ), we get ( n = 4(3) + 1 = 13 ). Continuing this process, valid two-digit numbers include 13, 21, 29, 37, 45, 53, 61, 69, 77, 85, 93, and 101.
Yes, unless you divide the number by itself, then the answer would be one. Also, you can divide it by one, and the answer would be that number.
No one knows
The largest remainder will be one less than the divisor. 7 - 1 = 6.
26 is one possibility
The remainder can only be one, so make it whatever number plus 1/2
Yes, unless you divide the number by itself, then the answer would be one. Also, you can divide it by one, and the answer would be that number.
63
It means that number can divide into the other number evenly, with no remainder.
No one knows
The largest remainder will be one less than the divisor. 7 - 1 = 6.
28 is one such number.
That is usually called the "remainder".
26 is one possibility
Oh, dude, yeah, totally! A remainder can definitely be a 2-digit number. It's just whatever is left over after you divide one number by another. So, like, if you divide 100 by 3, you get a remainder of 1, which is a 1-digit number. But if you divide 100 by 7, you get a remainder of 2 digits, which is totally cool too.
Yes, you can have a remainder of 5 when you divide by 6. If you divide 11 by 6, it will go into it one time with a remainder of 5.
When you divide any integer by 11, the largest possible remainder you can get is 10. This is because when you divide a number by 11, the remainders can range from 0 to 10. In this case, if the number being divided is one less than a multiple of 11, the remainder will be the largest possible, which is 10.
The remainder can only be one, so make it whatever number plus 1/2