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It seems there may be a typo in your function notation. If you meant to express the function as ( f(x) = -2(x^3) + 5 ), you can find a point on the graph by choosing a value for ( x ). For example, if ( x = 0 ), then ( f(0) = -2(0^3) + 5 = 5 ). Thus, the point ( (0, 5) ) lies on the graph of the function.
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It seems there is a typo in your function rule. If you meant ( f(x) = 10 + 4x ), then the points on the graph can be determined by substituting different x-values. For example, if ( x = 0 ), then ( f(0) = 10 ) (point (0, 10)). If ( x = 1 ), then ( f(1) = 14 ) (point (1, 14)). Other points can be calculated similarly.
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