Simply put, a velocity time graph is velocity (m/s) in the Y coordinate and time (s) in the X and a position time graph is distance (m) in the Y coordinate and time (s) in the X if you where to find the slope of a tangent on a distance time graph, it would give you the velocity whereas the slope on a velocity time graph would give you the acceleration.
The graph of velocity-time is the acceleration.
As, in the velocity-time graph, curves passes through zero means 'when time is zero velocity is zero'. Velocity is time derivative of displacement. So displacement is maximum or minimum when time is zero in position-time graph.
In a velocity-time graph it will be the time axis (where velocity = 0). On a distance-time graph it will be a line parallel to the time axis: distance = some constant (which may be 0).
If an x-t graph is a position-time graph, velocity is the slope of the line on the graph.
In a displacement-time graph, the gradient represents velocity. In a velocity-time graph, the gradient represents acceleration.
Your acceleration vs. Time graph is the slope of your velocity vs. time graph
To create an acceleration-time graph from a velocity-time graph, you need to find the slope of the velocity-time graph at each point. The slope represents the acceleration at that specific instant. Plot these acceleration values against time to get the acceleration-time graph.
To go from a position graph to a velocity graph, you can calculate the slope of the position graph at each point. The slope at any given point on a position vs. time graph represents the velocity at that specific time. Therefore, the velocity graph would be a plot of the slopes at each point on the position graph.
No, acceleration is the rate of change of velocity with respect to time. It is the derivative of the velocity function, not the slope of the velocity vs. time graph. The slope of the velocity vs. time graph represents the rate of change of velocity, not acceleration.
Two different distance-time graphs have matching velocity-time graphs when the slope of the distance-time graph represents the velocity in the velocity-time graph, as velocity is the derivative of distance with respect to time. This means that the steeper the distance-time graph, the greater the velocity on the velocity-time graph at that point.
No, displacement is the area under the velocity vs. time graph. The slope of a velocity vs. time graph represents acceleration.
A position time graph can show you velocity. As time changes, so does position, and the velocity of the object can be determined. For a speed time graph, you can derive acceleration. As time changes, so does velocity, and the acceleration of the object can be determined.If you are plotting velocity (speed) versus time, the slope is the acceleration.
Simply put, a velocity time graph is velocity (m/s) in the Y coordinate and time (s) in the X and a position time graph is distance (m) in the Y coordinate and time (s) in the X if you where to find the slope of a tangent on a distance time graph, it would give you the velocity whereas the slope on a velocity time graph would give you the acceleration.
The graph of velocity-time is the acceleration.
As, in the velocity-time graph, curves passes through zero means 'when time is zero velocity is zero'. Velocity is time derivative of displacement. So displacement is maximum or minimum when time is zero in position-time graph.
In a velocity-time graph it will be the time axis (where velocity = 0). On a distance-time graph it will be a line parallel to the time axis: distance = some constant (which may be 0).