The term "w width" typically refers to a specific measurement or dimension, often associated with the width of an object or item. In various contexts, such as clothing or footwear, it indicates the overall width of the product, which can affect fit and comfort. For example, in shoe sizing, a "w" may denote a wide width option, catering to individuals who require more space in their footwear.
Area= length * width length= width + 5 so.... Area= width * (width + 5) Area= width^2 + 5width (going to use w for width.) 66= w^2 + 5w w^2 + 5w - 66= 0 Now factor! (w - 6)(w + 11) Solve for w, and since area can't be negative, you get.. w=6 length= 6+5= 11
The dimensions are W and W+M where W is the width.
w=width
The width would be: P - (L*2) = W*2 Perimeter = P Length = L Width = W
Perimeter = length + length + width + width Let "w" = width, then "7w" must equal the length (because it's 7 times the width) 7w + 7w + w + w = perimeter 16w = perimeter
Area= length * width length= width + 5 so.... Area= width * (width + 5) Area= width^2 + 5width (going to use w for width.) 66= w^2 + 5w w^2 + 5w - 66= 0 Now factor! (w - 6)(w + 11) Solve for w, and since area can't be negative, you get.. w=6 length= 6+5= 11
8m Let the width of the table be w; then its length is w + 2. Area = length x width 80 = (w + 2)w w2 + 2w - 80 = 0 (w + 10)(w - 8) = 0 w = -10 or 8 As the width must be positive, it is 8m.
The dimensions are W and W+M where W is the width.
w=width
An adult emporer penguin's width woul be about 2-3 feet.
Generally - width is denoted by 'w' as inthe unit measurements are l:36", h: 24", w:18"Where l = length, h = height, and w - width.
The width would be: P - (L*2) = W*2 Perimeter = P Length = L Width = W
Perimeter = length + length + width + width Let "w" = width, then "7w" must equal the length (because it's 7 times the width) 7w + 7w + w + w = perimeter 16w = perimeter
The abbreviation for "width" is usually W, as in "H x D x W x", where "H" is height, "D" is depth, and "W" is width, when describing the size of a 3 dimensional object.
Suppose the width is W yards.Then twice the width is 2W yards3 yards less that twice the width is (2W - 3) yards.That is, the length is (2W - 3) yardsSo, the area = Length *Width = (2W - 3)*W which is known to be 27Therefore 2W2 - 3W = 27or 2W2 - 3W - 27 = 0so (W + 3)*(2W - 9) = 0so W = -3 or W = 4.5Since W cannot be negative, W = 4.5 yards and then L = 6 yards.Suppose the width is W yards.Then twice the width is 2W yards3 yards less that twice the width is (2W - 3) yards.That is, the length is (2W - 3) yardsSo, the area = Length *Width = (2W - 3)*W which is known to be 27Therefore 2W2 - 3W = 27or 2W2 - 3W - 27 = 0so (W + 3)*(2W - 9) = 0so W = -3 or W = 4.5Since W cannot be negative, W = 4.5 yards and then L = 6 yards.Suppose the width is W yards.Then twice the width is 2W yards3 yards less that twice the width is (2W - 3) yards.That is, the length is (2W - 3) yardsSo, the area = Length *Width = (2W - 3)*W which is known to be 27Therefore 2W2 - 3W = 27or 2W2 - 3W - 27 = 0so (W + 3)*(2W - 9) = 0so W = -3 or W = 4.5Since W cannot be negative, W = 4.5 yards and then L = 6 yards.Suppose the width is W yards.Then twice the width is 2W yards3 yards less that twice the width is (2W - 3) yards.That is, the length is (2W - 3) yardsSo, the area = Length *Width = (2W - 3)*W which is known to be 27Therefore 2W2 - 3W = 27or 2W2 - 3W - 27 = 0so (W + 3)*(2W - 9) = 0so W = -3 or W = 4.5Since W cannot be negative, W = 4.5 yards and then L = 6 yards.
A rectangle with length L and width W has perimeter = 2*(L+W) So, 2(6 + W) = 220 or 6 + W = 110 so that W = 104 Usually, Length > Width but clearly not in this case.
Length (L) equals area (A) divided by width (W); or L = A / W.