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What are the dimensions of a rectangle with the area of 27 yds sq. and the length is 3 yds less than twice the width?
Suppose the width is W yards.
Then twice the width is 2W yards
3 yards less that twice the width is (2W - 3) yards.
That is, the length is (2W - 3) yards
So, the area = Length *Width = (2W - 3)*W which is known to be 27
Therefore 2W2 - 3W = 27
or 2W2 - 3W - 27 = 0
so (W + 3)*(2W - 9) = 0
so W = -3 or W = 4.5
Since W cannot be negative, W = 4.5 yards and then L = 6 yards.
Suppose the width is W yards.
Then twice the width is 2W yards
3 yards less that twice the width is (2W - 3) yards.
That is, the length is (2W - 3) yards
So, the area = Length *Width = (2W - 3)*W which is known to be 27
Therefore 2W2 - 3W = 27
or 2W2 - 3W - 27 = 0
so (W + 3)*(2W - 9) = 0
so W = -3 or W = 4.5
Since W cannot be negative, W = 4.5 yards and then L = 6 yards.
Suppose the width is W yards.
Then twice the width is 2W yards
3 yards less that twice the width is (2W - 3) yards.
That is, the length is (2W - 3) yards
So, the area = Length *Width = (2W - 3)*W which is known to be 27
Therefore 2W2 - 3W = 27
or 2W2 - 3W - 27 = 0
so (W + 3)*(2W - 9) = 0
so W = -3 or W = 4.5
Since W cannot be negative, W = 4.5 yards and then L = 6 yards.
Suppose the width is W yards.
Then twice the width is 2W yards
3 yards less that twice the width is (2W - 3) yards.
That is, the length is (2W - 3) yards
So, the area = Length *Width = (2W - 3)*W which is known to be 27
Therefore 2W2 - 3W = 27
or 2W2 - 3W - 27 = 0
so (W + 3)*(2W - 9) = 0
so W = -3 or W = 4.5
Since W cannot be negative, W = 4.5 yards and then L = 6 yards.
What else can I help you with?
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The length of a rectangle is twice the width width the perimeter is 48 in find the dimensions of the rectangle?
Let the width of the rectangle be represented by "w" inches. Since the length is twice the width, it can be expressed as "2w" inches. The formula for the perimeter of a rectangle is P = 2(l + w), where P is the perimeter, l is the length, and w is the width. Substituting the given values into the formula, we get 48 = 2(2w + w). Simplifying, we find that 48 = 6w. Solving for w, we find that the width of the rectangle is 8 inches, and the length is 16 inches.
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