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What are the dimensions of a rectangle with the area of 27 yds sq. and the length is 3 yds less than twice the width?
Suppose the width is W yards.
Then twice the width is 2W yards
3 yards less that twice the width is (2W - 3) yards.
That is, the length is (2W - 3) yards
So, the area = Length *Width = (2W - 3)*W which is known to be 27
Therefore 2W2 - 3W = 27
or 2W2 - 3W - 27 = 0
so (W + 3)*(2W - 9) = 0
so W = -3 or W = 4.5
Since W cannot be negative, W = 4.5 yards and then L = 6 yards.
Suppose the width is W yards.
Then twice the width is 2W yards
3 yards less that twice the width is (2W - 3) yards.
That is, the length is (2W - 3) yards
So, the area = Length *Width = (2W - 3)*W which is known to be 27
Therefore 2W2 - 3W = 27
or 2W2 - 3W - 27 = 0
so (W + 3)*(2W - 9) = 0
so W = -3 or W = 4.5
Since W cannot be negative, W = 4.5 yards and then L = 6 yards.
Suppose the width is W yards.
Then twice the width is 2W yards
3 yards less that twice the width is (2W - 3) yards.
That is, the length is (2W - 3) yards
So, the area = Length *Width = (2W - 3)*W which is known to be 27
Therefore 2W2 - 3W = 27
or 2W2 - 3W - 27 = 0
so (W + 3)*(2W - 9) = 0
so W = -3 or W = 4.5
Since W cannot be negative, W = 4.5 yards and then L = 6 yards.
Suppose the width is W yards.
Then twice the width is 2W yards
3 yards less that twice the width is (2W - 3) yards.
That is, the length is (2W - 3) yards
So, the area = Length *Width = (2W - 3)*W which is known to be 27
Therefore 2W2 - 3W = 27
or 2W2 - 3W - 27 = 0
so (W + 3)*(2W - 9) = 0
so W = -3 or W = 4.5
Since W cannot be negative, W = 4.5 yards and then L = 6 yards.
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FranSuppose the width is W yards.
Then twice the width is 2W yards
3 yards less that twice the width is (2W - 3) yards.
That is, the length is (2W - 3) yards
So, the area = Length *Width = (2W - 3)*W which is known to be 27
Therefore 2W2 - 3W = 27
or 2W2 - 3W - 27 = 0
so (W + 3)*(2W - 9) = 0
so W = -3 or W = 4.5
Since W cannot be negative, W = 4.5 yards and then L = 6 yards.
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