To find the equation of a line perpendicular to ( y = 4x + 3 ), we first determine the slope of the given line, which is 4. The slope of a line perpendicular to it is the negative reciprocal, so it would be ( -\frac{1}{4} ). Using the point-slope form ( y - y_1 = m(x - x_1) ) with the point (-8, 5) and the slope ( -\frac{1}{4} ), the equation becomes ( y - 5 = -\frac{1}{4}(x + 8) ). Simplifying this gives the equation of the perpendicular line.
2-3
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
Perpendicular lines passing through a point are at right angles to each other.
Perpendicular slope: 1/2 Perpnedicular equation: y-5 = 1/2(x-2) => y = 0.5x+4
Yes, I could, if I knew the slope of the line given.
2-3
That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.
That would depend on its slope which has not been given.
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
General formula
Perpendicular lines passing through a point are at right angles to each other.
Perpendicular slope: 1/2 Perpnedicular equation: y-5 = 1/2(x-2) => y = 0.5x+4
If you mean y = 3x+8 then the perpendicular slope will be -1/3 and the equation works out as 3y = -x+9
Yes, I could, if I knew the slope of the line given.
If you mean point (-1, 4) and equation of 4x-3y = -9 then y = 4/3x+3 Slope of equation: 4/3 Perpendicular slope: -3/4 Perpendicular equation: y-4 = -3/4(x--1) => 4y = -3x+13
Slope of line: 3 Perpendicular slope: -1/3 Equation: y-2 = -1/3(x-0) => y = -1/3x+2
Slope: -2 Equation: y--1 = -2(x-3) => y = -2x+5