Points: (-3, 6) and (-2, 4)
Slope: -2
Equation: y = -2x
If you mean: y = mx+b then it is in slope intercept form
No, not every equation of the form (x^2 + mx + y^2 + ny = p) represents a circle. For an equation to represent a circle, it must be in the standard form ((x - h)^2 + (y - k)^2 = r^2), where (r) is the radius. The presence of linear terms (mx) and (ny) means that the equation could represent a different conic section, such as an ellipse or hyperbola, depending on the values of (m), (n), and (p).
Use the slope intercept form equation, y=mx+b. Plug in -2 for m and 8 for b. Final equation: y=-2x+8
In slope-point form a line with slope m through point (X, Y) has equation: y - Y = m(x - X) → y = mx + Y - mX → y = mx + c where: m is the slope c = Y - mx is the intercept → The line with slope 2 through the point (1, 1) has equation: y = 2x + 1 - 2×1 → y = 2x - 1
UndefinedImproved Answer:-The straight line equation is: y = 2x
If you mean: y = mx+b then it is in slope intercept form
No, not every equation of the form (x^2 + mx + y^2 + ny = p) represents a circle. For an equation to represent a circle, it must be in the standard form ((x - h)^2 + (y - k)^2 = r^2), where (r) is the radius. The presence of linear terms (mx) and (ny) means that the equation could represent a different conic section, such as an ellipse or hyperbola, depending on the values of (m), (n), and (p).
No, y=x^2 + 2 is a quadratic equation. A linear equation is one in the form y=mx+b. A quadratic has a form y=ax^2+bx+c.
The equation of the line passing through the points (mx, ny) and (2, 5) is y ((5-ny)/(2-mx))x (5 - ((5-ny)/(2-mx))2).
Use the slope intercept form equation, y=mx+b. Plug in -2 for m and 8 for b. Final equation: y=-2x+8
In slope-point form a line with slope m through point (X, Y) has equation: y - Y = m(x - X) → y = mx + Y - mX → y = mx + c where: m is the slope c = Y - mx is the intercept → The line with slope 2 through the point (1, 1) has equation: y = 2x + 1 - 2×1 → y = 2x - 1
The slope-intercept form of an equation is: y = mx + b Just copy down this equation, then replace "m" with the slope, and "b" with the y-intercept.
UndefinedImproved Answer:-The straight line equation is: y = 2x
An equation such as y = mx + c is said to be in standard form. From such an equation, Gradient = coefficient of x = 3
b=-2
1.Put into y=mx=b 2.graph 3. find ordered pair where the lines intersect
The equation of a line written in slope intercept form has the form of y = mx + b. In this form, m is the slope of the line and b is the y intercept.