In slope-point form a line with slope m through point (X, Y) has equation:
y - Y = m(x - X)
→ y = mx + Y - mX
→ y = mx + c
where:
m is the slope
c = Y - mx is the intercept
→ The line with slope 2 through the point (1, 1) has equation:
y = 2x + 1 - 2×1
→ y = 2x - 1
y=2x+1
y=3x-3
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
The equation is: y-2 = 2(x-4) => y = 2x-2
It is: y--5 = -3(x-4) => y = -3x+12-5 => y = -3x+7 in slope-intercept form
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
Slope: -3 Point: (4, -5) Equation: y = -3x+7
y=2x+1
y=3x-3
y=2x+13
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
The answe iss..... 6
y=2x+1
y = 2x - 1
It is: y = 2x-6
no it is different
y-9 = 3(x-4) y = 3x-3 in slope intercept form