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What is the equation of the line with slope 5 that contains point (-2 -3)?
Slope: 5 Points: (-2, -3) Equation: y = 5x+7
What is the equation of the line that passes through (4 -1) and (-2 3)?
Points: (4, -1) and (-2, 3) Slope: -2/3 Equation: 3y = -2x+5
What is the length of the line including its equation and its perpendicular bisector equation that spans the points of 2 3 and 5 7 showing work?
Points: (2, 3) and (5, 7)Midpoint: (2+5)/2 and (3+7)/2 = (3.5, 5)Length: square root of (2-5)2+(3-7)2 = 5Slope: (3-7)/(2-5) = 4/3Perpendicular slope: -3/4Equation: y-3 = 4/3(x-2) => 3y = 4x+1Perpendicular equation: y-5 = -3/4(x-3.5) => 4y = -3x+30.5
What is the length of the line and its equation including its perpendicular bisector equation that spans the points of 2 3 and 5 7 on the Cartesian plane showing key stages of work?
Points: (2, 3) and (5, 7)Length: 5 unitsSlope: 4/3Perpendicular slope: -3/4Midpoint: (3.5, 5)Equation: 3y = 4x+1Bisector equation: 4y = -3x+30.5
What is the equation of the line that passes through the points negative 2 2 and 0 5?
Just to be clear, the two points are (-2,2) and (0,5). The slope (rise/run) is (5-2)/(0 - -2) = 3/2. So y = (3/2)*x + b. Put one of the point into this and solve for b: 5 = (3/2)*0 + b; b = 5. The equation is y = (3/2)*x + 5. Do a check that the other point (-2,2) satisfies this equation {and it does}.
