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Indicate in standard form the equation of the line passing through the given points of 4 1 and 5 2?
Points: (4, 1) and (5, 2) Slope: 1 Equation: y = x-3 Equation in its general form: x-y-3 = 0
What is the equation of a line that passes through the points 2 5 and 4 3?
Points: (2, 5) and (4, 3) Slope: -1 Equation: y = -x+7 in slope-intercept form --- If you want to write the slope-intercept form of the equation of the line passing through the given points, then use the two points to find the slope of the line. After that, use the slope and one of the points to find the y-intercept. For instance, m = (5 - 3)/(2 - 4) = 2/-2 = -1(the slope) y = mx + b (replace m with -1, and (x, y) with (4, 3)) 3 = -1(4) + b 3 = -4 + b (add 4 to both sides) 7 = b Thus, y = -x + 7 is the equation of the line passing through (2, 5) and (4, 3).
How do you get a solution set?
The solution set for a given equation is the set of all points such that their coordinates satisfy the equation.
What is the equation of the circle through -2 -4 60 and 15?
Given any two points, there are infinitely many coplanar circles that can go through the two points. And then each circle can be rotated through infinitely many planes about the straight line joining those two points. So as stated, there is not the slightest hope of pinning down an answer.
What points are on the line given by the equation y equals 3x-1?
4
Indicate in standard form the equation of the line passing through the given points of 4 1 and 5 2?
Points: (4, 1) and (5, 2) Slope: 1 Equation: y = x-3 Equation in its general form: x-y-3 = 0
Does the line passing through the points 2 4 and 6 8 intersect a line with a slope of 5 and y-intercept of 3?
No becaue the given points results as an equation of: y = x+2
Which is not an equation of the line that passes through the points 1 1 and 5 5?
The equation for the given points is y = x+4 in slope intercept form
What is the given points for the equation y equals 2x-3?
5
How do you find the slope of a line passing through a given pair of points?
To find the slope of a line passing through a given pair of points is found by using the point slope formula. Y(2)-Y(1) over x(2) -x(1).
What is the slope of a line passing through the two points - Round your answer to the nearest tenth?
That depends on the points in order to find the slope whereas no points have been given.
What points are on the line given by the equation y -3x 5?
But it's not an equation because there is no equal sign and no points are given.
How do you write an equation in slope-intercept form of the line passing through each pair of points?
y=mx+c where x and y are variables, m is the gradient (or slope) and c is the intercept on y (axis). that is the general equation of a straight line. if you had given some coordinates for the points one could extrapolate from that to find the full equation. since you have not, one cannot.
What is the equation of a line passing through (-6 5) and having a slope of?
The straight line equation would depend on the slope which has not been given.
Find the equation of the line passing through the given point and perpendicular to the given line (5, 9); x-5y=8?
y = -(1/5)x + 9
What is the equation of a line that passes through the points 2 5 and 4 3?
Points: (2, 5) and (4, 3) Slope: -1 Equation: y = -x+7 in slope-intercept form --- If you want to write the slope-intercept form of the equation of the line passing through the given points, then use the two points to find the slope of the line. After that, use the slope and one of the points to find the y-intercept. For instance, m = (5 - 3)/(2 - 4) = 2/-2 = -1(the slope) y = mx + b (replace m with -1, and (x, y) with (4, 3)) 3 = -1(4) + b 3 = -4 + b (add 4 to both sides) 7 = b Thus, y = -x + 7 is the equation of the line passing through (2, 5) and (4, 3).
What is the equation of the line passing through the points 2 3 and 4 -1?
The equation of a line with gradient m passing through point (xo, yo) is given by: y - yo = m(x - xo) The gradient m is calculated: m = change_in_y/change_in_x = y1-y0/x1-x0 → line through points po (2, 3) and p1 (4, -1) has equation: y - 3 = (-1 - 3)/(4 - 2) (x - 2) → y - 3 = -4/2 (x - 2) → y - 3 = -2(x - 2) → y - 3 = -2x + 4 → y + 2x = 7
