a straight line with a slope of 1
with an intersection at point (0, 0)
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Set 'x' equal to zero, and solve the remaining equation for 'y'.
You are solving for x and y. If x is set equal to 1 and y is set equal to 4, then you have 5-20=-15. You can graph this by placing a point on the graph corresponding to x and y. That is, on the x axis you would go over 1 and on the y axis you would go up 5. Now if x is set equal to 5, then that is 25, so y must be set equal to 10. This is 25-40=-15. Then on the same graph, you go over 5 on the x axis and go up 10 on the y axis. Now you can draw a line between the two. All you have to do now is solve the equation for another set of numbers, and then put that point on the graph. With three points, you have sufficient information.
Not quite. The polynomial's linear factors are related - not equal to - the places where the graph meets the x-axis. For example, the polynomial x2 - 5x + 6, in factored form, is (x - 2) (x - 3). In this case, +2 and +3 are "zeroes" of the polynomial, i.e., the graph crosses the x-axis. That is, in an x-y graph, y = 0.
One such function is [ Y = INT(x) ]. (Y is equal to the greatest integer in ' x ')
Just label one axis x and the other axis y. Voila!! x y graph!