The common multiples of a number with itself are the multiples of that number. Thus all multiples of A between 1 and 100 are the common multiples of A and A between 1 and 100.
There are an infinite number of fractions between 1 and 100. I don't have the time right now . . .
To find the average of integers, add them all together then divide the total by the number of integers.
The average is all the numbers added together and divided by how many numbers there are. In this case: 78+100=178. 178/2=89. Therefore the mean/average of the two numbers is 89.
the mean is the average of all the salaries an the the median is the number that falls in the middle
15
545
269
1060
The common multiples of a number with itself are the multiples of that number. Thus all multiples of A between 1 and 100 are the common multiples of A and A between 1 and 100.
There are an infinite number of fractions between 1 and 100. I don't have the time right now . . .
50 this isnt quite right, 50 is the answer if dividing by two. if all the numbers between 1 and 100 where written out in a line and then you crossed of one number from each end at a time you end up with 50 and 51 left in the middle. in other words you do not get one whole number (an integer) the answer would have to 50.5.
1 to 5
101
To find the average of a set of numbers, you add all the numbers together and then divide by the total number of values. In this case, the sum of 96, 100, and 92 is 288. Dividing 288 by 3 (the total number of values) gives an average of 96.
To find the average of integers, add them all together then divide the total by the number of integers.
The average is all the numbers added together and divided by how many numbers there are. In this case: 78+100=178. 178/2=89. Therefore the mean/average of the two numbers is 89.