If you can mash the equation for the parabola into the form Y = Ax2 + Bx + C, then the parabola opens up if 'A' is positive, and down if 'A' is negative.
y= ax2+bx+c
y = ax2 + c is a parabola, c is the y intercept of the parabola. It also happens to be the max/min of the function depending if a is positive or negative.
If the equation of the parabola isy = ax^2 + bx + c then the roots are [-b +/- sqrt(b^2-4ac)]/(2a)
If the equation of the parabola isy = ax^2 + bx + c then the roots are [-b +/- sqrt(b^2-4ac)]/(2a)
The general equation for a parabola is y = ax^2 + bx + c, where a, b, and c are constants that determine the shape, orientation, and position of the parabola.
An equation that when plotted produces a parabola is a quadratic equation of the form y = ax2 + bx + c where a, b and c are constants.
If you can mash the equation for the parabola into the form Y = Ax2 + Bx + C, then the parabola opens up if 'A' is positive, and down if 'A' is negative.
X = Ay2 + By + C
y= ax2+bx+c
y = ax2 + c is a parabola, c is the y intercept of the parabola. It also happens to be the max/min of the function depending if a is positive or negative.
The answer depends on what information you have and what form you are checking.The functional form of a parabola is y = ax2+ bx + c where a, b and c are real and a >0. If that is the case then, functionally it is a parabola.The graph of a parabola has a single turning point and is symmetric about its axis. But that is not enough. The graph of y = ax4+ bx2 + c or y = ax6+ bx3+ c have similar shapes but they are not parabolas.Find the axis. This should be easy because the parabola is symmetric about its axis. Draw a number of lines parallel to the axis. Where they meet the parabola, reflect them. These reflected lines should all meet at the same point which is the focus of the parabola.
If the equation of the parabola isy = ax^2 + bx + c, then it opens above when a>0 and opens below when a<0. [If a = 0 then the equation describes a straight line, and not a parabola!].
If the equation of the parabola isy = ax^2 + bx + c then the roots are [-b +/- sqrt(b^2-4ac)]/(2a)
If the equation of the parabola isy = ax^2 + bx + c then the roots are [-b +/- sqrt(b^2-4ac)]/(2a)
The general form is y = ax2 + bx + c where a b and c are constants and a is not 0
y = ax^2 + c where a and c are constants and a is not 0.